200
The position of vectors of points P and Q ( 3, 2, 1 ) and (-2, 2, -4 ) respectively. The origin is at O. Find
a)the angle POQ;
b)the area of the triangle OPQ
a) dot product: (3)(-2) + (2)(2) + (1)(-4) = -6
magnitude: √(3^2 + 2^2 +1^2) = √14
√(-2^2 + 2^2 + -4^2) = √24
cos θ = -6 / (√140)(√24)
θ = 109.1
b)-10i + 10j + 10k
magnitude:√300
Area = √300 / 2