What is the center & radius, given the equation
(x-2)2+(y-5)2=92, the center point and radius of the circle are..
(2,5) r=9
The center is (1,-3) and the radius is 2
(x-1)2 + (y+3)2 = 4
Center: (2, −5) Point on Circle: (−7, −1)
(x − 2)2 + (y + 5)2 = 97
x2 + y2 = 64 Point: (0, −9)
Outside
x2+ 8x +y2 − 2y = 64
(x+4)2 + (y-1)2 = 81
(x-3)2+(y-4)2=25, the center point and radius of the circle are..
(3,4) r=5
The center is (2,-1) and the radius is 4..
(x-2)2 + (y+1)2 = 16
Center: (14, 17) Point on Circle: (15, 17)
(x − 14)2 + (y − 17)2 = 1
(x-1)2 + (y-3)2 = 36 Point: (4, 7)
Inside
x2 + 2x + y2 - 10y = 55
(x + 1)2 + (y − 5)2 = 81
(x+8)2+(y+17)2=49, the center point and radius of the circle are..
(-8,-17) r=7
The center is (1,-4) and the diameter is 6..
(x-1)2 + (y+4)2 = 9
Ends of a diameter: (−17, −9) and (−19, −9)
(x + 18)2 + (y + 9)2 = 1
x2 + y2 + 10x − 4y = 140 Point: (7, −3)
On
y2 + 2x + x2 = 24y − 120
(x + 1)2 + (y − 12)2 = 25
(x-2)2+(y+5)2=289, the center point and radius of the circle are..
(2,-5) r=17
The center is (0,3) and the radius is √14
x2 + (y-3)2 = 14
Ends of a diameter: (−3, 11) and (3, −13)
x2 + (y + 1)2 = 153
x2 + y2 − 6x − 10y + 16 = 0 Point: (6, 2)
On
x2 + y2 + 14x − 12y + 4 = 0
(x + 7)2 + (y − 6)2 = 81
(x-1)2+(y-2)2=20, the center point and radius of the circle are..
(1,2) r=2sqrt(5)
The center is (13,-13) and the diameter is 8√2
(x − 13)2 + (y + 13)2 = 32
Center: (−2, 12) Tangent to x = −5
(x + 2)2 + (y − 12)2 = 9
x2 + y2 + 2x + 8y − 13 = 0 Point: (−4, 1)
Outside
8x + 32y + y2 = −263 − x2
(x + 4)2 + (y + 16)2 = 9