2x + 5 = 13
x = 4
3x - 12 = 6
x = 6
-2x - 1 = 7
x = -4
-10 = 4 - 2x
x = 7
2x + 1 = 1
x = 0
2x + 3x = 15
x = 3
4x - x = -9
x = -3
7x + 8x + 5x = 20
x = 1
-3x - 2x - 7x = 24
x = -2
16 = x + 7x
x = 2
-3(x+2) = 6
x = -4
−3(4x−8)=−36
x = 5
6(−x−3) = 24
x = -7
3(−6x−5) = 75
x = -5
5(1 - 2x)= 85
x = -8
28 - 4x = x - 17
x = 9
39 - 3x = x + 7
x = 8
13x + 8 = 10 + 12x
x = 2
x - 4 = 28 + 5x
x = -8
20x - 11 = 4 + 15x
x = 3
In the equation 2(x + 4) = 2x + 8, which number(s) should be changed to make the equation have no solutions?
You can change the 4 or the 8 so the sides will have different constants.
If the equation 5(3x+6)=3(5x+k) has infinitely many solutions, what is the value of k?
x−1=5x+3x−8
x = 1
−18−6x=6(1+3x)
x = -1
Give an example of an equation with variables on both sides with exactly one solution and explain why it has one solution.
Any equation with different coefficients is correct.