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100

2x + 5 = 13

x = 4

100

3x - 12 = 6

x = 6

100

-2x - 1 = 7

x = -4

100

-10 = 4 - 2x

x = 7 

100

2x + 1 = 1

x = 0

200

2x + 3x = 15 

x = 3

200

4x - x = -9

x = -3

200

7x + 8x + 5x = 20

x = 1

200

-3x - 2x - 7x = 24

x = -2

200

16 = x + 7x 

x = 2

300

-3(x+2) = 6

x = -4

300

−3(4x−8)=−36


x = 5

300

6(−x−3) = 24


x = -7

300

3(−6x−5) = 75

x = -5

300

5(1 - 2x)= 85


x = -8

400

28 - 4x = x - 17

x = 9

400

39 - 3x = x + 7

x = 8

400

13x + 8 = 10 + 12x

x = 2

400

x - 4 = 28 + 5x

x = -8

400

20x - 11 = 4 + 15x

x = 3

500

In the equation 2(x + 4) = 2x + 8, which number(s) should be changed to make the equation have no solutions?

You can change the 4 or the 8 so the sides will have different constants. 

500

If the equation 5(3x+6)=3(5x+k) has infinitely many solutions, what is the value of k?

k = 10 so each side will have the variable of 30. 
500

x−1=5x+3x−8


x = 1

500

−18−6x=6(1+3x)


x = -1

500

Give an example of an equation with variables on both sides with exactly one solution and explain why it has one solution.

Any equation with different coefficients is correct. 

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