Geometry applications
Percent Applications
Simplifying
100
Generate 2 equivalent expressions that could be used to find the perimeter of any rectangle.
l + l + w + w
2(l) + 2(w)
2 (l+w)
100
1) .45
2) .67
3) .6
4) .03
100
-3x + 5 - 1/3x -10
- 3 1/3x -5
200
Chaplin says that the expression 4y-2 + 2y could be used to determine the perimeter of the rectangle. Do you agree? If yes, generate an equivalent expression that could also be used. If no, explain the mistake that was made and how he could change his expression so that it is correct.
Chaplin is incorrect. His expression only measures two of the four sides. He could change his expression the following ways.
1) Multiply his entire expression by 2. 2 (4y - 2 + 2y)
2) Add the length and width twice. (4y - 2) + (4y - 2) + (2y) + (2y)
3) Multiply the length by 2 and the width by 2. 2(4y-2) + 2(2y)
200
A student received a coupon for 17% off the total purchase price at a clothing store. Let b represent the original price of the purchase. Use the expression b - 0.17b for the new price of the purchase. Write an equivalent expression by combining like terms.
.83b
200
1/2 (4x - 6) - (x - 3)
x
300
Generate 3 expressions that could be used to find the perimeter of the rectangle below. Then, simplify each expression to prove they are equivalent.
(x + 8) + (x + 8) + (1/3x +2) + (1/3x + 2)
2 2/3x + 20
2 ((x+8)+(1/3x + 2))
2 2/3x + 20
2(x + 8) + 2(1/3x + 2)
2 2/3x + 20
300
p + .25p
1.25p
300
Factor the expression using the greatest common factor.
18m - 12r + 36
6 (3m - 2r + 6)