Evaluate
f(x) = x + 5,
when f(10)
x = 15
f(x) = x^3 + 4
g(x) = 2x - 12
h(x) = x^2 - 2x + 3
Evaluate f(1)
x = 5
Is this a function?
Yes, because it passes the vertical line test
Suppose that the water level of a river is 34 feet and that it is receding at a rate of 0.5 foot per day. This scenario can be shown by the equation W(x)=34-0.5(x), where x is number of days gone by. What is the water level after 6 days ?
W(6)=
31 feet
-2+3
1
Evaluate
f(x) = 3x - 2,
when f(5)
x = 13
f(x) = x^3 + 4
g(x) = 2x - 12
h(x) = x^2 - 2x + 3
Evaluate g(-2)
x = -16
Is this a function?
Yes it is a function, because it passes the vertical line test.
For babysitting, Nicole charges a flat fee of $3, plus $5 per hour.This can be modeled by the equation f(x)=5x+3, where x ia hours. How much money will she get after 4 hours?
f(4)=
$23
-8+8
0
Evaluate
f(x) = 2x - 6,
when f(-10)
x = -26
f(x) = x^3 + 4
g(x) = 2x - 12
h(x) = x^2 - 2x + 3
Evaluate f(-2)
x = -4
Is this a function?
26
No, because it does not pass the vertical line test
. Jason jumped off a cliff into the ocean in Acapulco while vacationing with some friends. His height as a function of time could be modeled by the function h(t) = -16t2 + 16t + 480 , where t is the time in seconds and h is the height in feet. How high was he in the air after 2 seconds?
h(2)=
448 ft.
2-8+10
4
Evaluate
g(x) = x^2 + 5,
when g(2)
x = 9
f(x) = x^3 + 4
g(x) = 2x - 12
h(x) = x^2 - 2x + 3
Evaluate h(-3)
x = 18
Is this a function?

Yes, because there is one output for every input.
Bacteria in a pertri dish starts of with 3 milliograms, it doubles every day. This scenario can be repressnted by the exponential equaion g(x)=3(2)x. How many kilograms will be in the dish after 4 days?
g(4)=
48 millograms
-10+7-6
-9
Evaluate
g(x) = x^2 - 10,
when g(-5)
x = 15
f(x) = x^3 + 4
g(x) = 2x - 12
h(x) = x^2 - 2x + 3
Evaluate g(3)
x = -6
Is this a function?
No, because 2 goes to two different outputs. So, the function is one-to-many and thus not a function.
An object is launched at 19.6 meters per second (m/s) from a 58.8-meter tall platform. The equation for the object's height s at time t seconds after launch is s(t) = –4.9t2+ 19.6t + 58.8, where s is in meters. How far had the object gone after 1 second?
s(1)=
73.5 meeters
3-8+10-4
1