500
Calculate the ΔH°, ΔS°, and ΔG° of the following reaction: 2CH3OH(g) + H2(g) -> C2H6(g) + 2H2O(g).
ΔH°(CH3OH, g) = -201.2 kJ/mol, ΔS°(CH3OH, g) = 237.6 J/mol-K, ΔG°(CH3OH, g) = -161.9 kJ/mol
ΔH°(H2, g) = 0 kJ/mol, ΔS°(H2, g) = 130.58 J/mol-K, ΔG°(H2, g) = 0 kJ/mol
ΔH°(C2H6, g) = -84.68 kJ/mol, ΔS°(C2H6, g) = 229.5 J/mol-K, ΔG°(C2H6, g) = -32.89 kJ/mol
ΔH°(H2O, g) = -241.82 kJ/mol, ΔS°(H2O, g) = 188.83 J/mol-K, ΔG°(H2O, g) = -228.75 kJ/mol
ΔH° = 2(-241.82) + -84.68 – (0 + 2*-201.2) = -165.92 kJ
ΔS° = 2(188.83) + 229.5 – (130.58 + 2*237.6) = 1.38 J/K
ΔG° = 2(-228.57) + -32.89 – (0 + 2*-161.9) = -166.23 kJ