Significant Figures
Scientific Notation
Dimensional Analysis
Percent Error
Accuracy vs Precision
100
How many Sig Figs are in 1.3
2
100
Convert the number 5,000 to scientific notation.
5 x 103
100
Convert 5 kilometers to meters using dimensional analysis
5,000 meters
100
How do you calculate percent error?
100
Define accuracy in scientific terms.
Is a measure of how close a measurement comes to the actual value of whatever is measured
200
How many significant figures are in the number 0.00456?
3
200
What is the scientific notation for the number 0.00034?
3.4 x 10-4
200
How many seconds are in 3.5 hours using dimensional analysis?
12,600 seconds
200
If the accepted value of a measurement is 50 and the experimental value is 48, what is the percent error?
4%
200
Define precision in scientific terms.
Is a measurement of how close a series of measurements are to one another
300
round 0.00789 to two significant figures.
0.0079
300
Multiply (3.0 x 102) by (2.0 x 103) and express the answer in scientific notation.
6.0 x 105
300
8300 dam = ___________________ mi
(51 mi)
300
How do you calculate error?
Error = Experimental value - Accepted Value
300
Give an example of a scenario where a measurement is precise but not accurate.
Imagine you have a thermometer that consistently reads 98.5°C every time you measure the temperature of boiling water. The accepted or true boiling point of water at standard atmospheric pressure is 100.0°C.
400
In the calculation (2.45 + 3.1), what would the answer be rounding to the correct number of significant figures?
5.6
400
(1.2 x 104) + (3.4 x 105) in scientific notation?
3.5 ×105
400
Convert 56.7 m2 to cm2
(5.67 x 105 cm2)
400
Calculate the percent error if the accepted value is 20.0 and the measured value is 18.5.
7.5%
400
Distances between two lockers = 458 cm
Student measurements = 462 cm, 451 cm, 475 cm
How would you describe this data
neither precise or accurate
500
In the calculation (0.002 x 3.1), what would the answer be rounding to the correct number of significant figures?
0.006
500
(7.5×10−3)−(2.4×10−4)
7.3×10−3
500
230.2 mg/mL → kg/L
0.2302 kg/L
500
A student calculate the density as 1.40 g/L. The accepted density value is 1.36 g/L. What is the percent error of the student’s measurement?
2.94%
500
distances between two lockers = 458 cm
Student measurements = 458 cm, 459 cm, 457 cm
How would you describe this data
very accurate