Linear
For the linear equation
y = 3x - 2
calculate the value of y when
x = 4
y = 10
Expand and simplify
(x + 4)(x + 3)
x^2 + 7x + 12
Write 0.68 as a percentage
68%
Question 1
Answer 1
Write 0.55 as a fraction in its simplest form
55 / 100
= 11 / 20
Find the x-intercept and y-intercept of
y = 2 x - 6
x = 3
y = -6
Expand and simplify
(2x - 3)(3x + 4)
6x^2 + 8x - 9x - 12
= 6x^2 - x - 12
A jacket costs $120. Its price increases by 15%. Calculate the new price.
$138
Question 2
Answer 2
Factorise by grouping
3a + ab + 6 + 2b
= (3 + b)(a + 2)
Complete a table of values for
y = 1/2 x + 3
using x = -4, -2, 0, 2, 4
x -4 -2 0 2 4
y 1 2 3 4 5
Factorise
x^2 + 7x + 10
(x + 5)(x + 2)
30% of an amount is $54. Find the original amount.
$180
Question 3
Answer 3
A phone costs $240 and is discounted by 20%. Calculate the sale price.
$192
Sketch
y = -2 x + 4
on a set of axes. Clearly label both intercepts with their coordinates
x and y axis labels
(0, 4)
(2, 0)
straight line connecting both points
Find the turning point of
x^2 - 6x + 5
(x - 5)(x - 1)
x = 5 x = 1
axis of symmetry: x = 3
(3, -4)
Calculate the simple interest earned on $2500 invested at 6% per annum for 4 years. Find the total amount in the account.
$3100
Question 4
Answer 4
Find the x-intercepts and turning point of
y = x^2 - 4x - 12
x-intercepts: (-2, 0) (6, 0)
turning point: (2, -16)
Find the point of intersection of the two lines
y = 2x - 3
y = -x + 6
(3, 3)
Sketch
y = x^2 + 2x - 8
Label both x-intercepts, the y-intercept and the turning point with their coordinates
x-intercepts: (-4, 0) and (2, 0)
y intercept: (0, -8)
turning point: (-1, -9)
connecting curve
Two investments of $6000 earn simple interest for 5 years.
Investment A earns 4% p.a. and Investment B earns 7% p.a.
How much more interest does Investment B earn?
A = $1200
B = $2100
Difference = $900
Question 5
Answer 5
Sketch both:
y = x^2 - 4
y = x + 2
Find and label their points of intersection
(-2, 0)
(3, 5)