Exception Handling

Error Types

100

Identify the error(s) in the code:

# Code snippet

numbers = [1, 2, 3, 4] 

print(numbers[4])

Index Error: The list numbers has indices from 0 to 3, so accessing numbers[4] will raise an IndexError. 

200

Identify the error(s) in the code:

# Code snippet

def divide(a, b):

    return a / b

result = divide(10, 0)

print(result)

ZeroDivisionError: Dividing by zero in the divide function will raise a ZeroDivisionError.

300

Identify the error(s) in the code:

# Code snippet

my_dict = {'name': 'Alice', 'age': 25}

print(my_dict['gender'])

KeyError: The key 'gender' does not exist in my_dict, so accessing it will raise a KeyError.

400

Identify the error(s) in the code:

# Code snippet

data = [10, 20, 30]

index = int('three')

print(data[index])

ValueError: Converting the string 'three' to an integer with int('three') will raise a ValueError.

IndexError: If the string 'three' were a valid integer conversion but out of range, it would cause an IndexError. However, in this specific case, only the ValueError applies.

500

Identify the error(s) in the code:

# Code snippet

data = {'name': 'Alice', 'scores': [85, 90, 78]}

try:

    average_score = sum(data['scores']) /                 len(data['score'])

    print("Average score:", average_score)

    last_score = data['scores'][3]

    print("Last score:", last_score)

except Exception as e:

    print(e)

KeyError: The key 'score' is incorrect. It should be 'scores' in len(data['score']).

IndexError: The list data['scores'] has indices 0, 1, and 2. Accessing data['scores'][3] will raise an IndexError.

Handling exceptions using Try and Except

100

What will the following code output:

Input:

6.4

3.2

Code:

try:

    value1 = float(input("Enter a floating point number: "))

    print(value1 / 2)

    value2 = float(input("Enter another floating point number: "))

    print(10 / value2)

except:

    print('Error occurred')

print('End of program')

3.2

3.125

End of Program

200

What will the following code output:

Input:

not_a_number

3.2

code:

try:

    value1 = float(input("Enter a floating point number: "))

    print(value1 / 2)

    value2 = float(input("Enter another floating point number: "))

    print(10 / value2)

except:

    print('Error occurred')

print('End of program')

Error occurred

End of program

300

What will the following code output:

Input:

1

6

eight

0

end

code:

user_input = input()

while user_input != 'end':

    try:

        divisor = int(user_input)

        print(60 // divisor)

    except ValueError:

        print('v')

    except ZeroDivisionError:

        print('z')

    user_input = input()

print('OK')

60

10

v

z

OK

400

What will the following code output:

Input:

-10, 90, 4, seven,-2,0,end

code:

numbers = [2, 4, 5, 8]

user_input = input()

while user_input != 'end':

    try:

        divisor = int(user_input)

        if divisor > 20:

            result = compute(result)

        elif divisor < 0:

            result = numbers[divisor]

        else:

            result = 20 // divisor

        print(result, end=' ')

    except (ValueError, ZeroDivisionError):

        print('r', end=' ')

    except (NameError, IndexError):

        print('s', end=' ')

    user_input = input()

print('OK')

output:

s s 5 r 5 r OK

500

What will the following code output:

Input:

four,0,4,-8,zero, 5

code:

user_input = input()

while user_input != 'end':

    try:

        divisor = int(user_input)

        if divisor < 0:

            print(compute(divisor), end=' ')

        else:

            print(20 // divisor, end=' ')

    except ValueError:

        print('v', end=' ')

    except ZeroDivisionError:

        print('z', end=' ')

    except:

        print('x', end=' ')

    user_input = input()

print('OK')

output:

v z 5 x v 4 OK

Raising Errors/General

100

A block of code that utilizes exception handling

What is a try block?

200

True or False:

If no exception occurs, the code will skip over the except and finally clauses and continue with the rest of the code

False:

If no exception occurs, the except clause WILL BE SKIPPED while the finally clause WILL NOT BE SKIPPED.

300

What will the following code output:

function call: divide(9,3)

def divide(a, b):

    z = -7

    try:

        z = a / b

    except ZeroDivisionError:

        print('Can't divide by 0')

    finally:

        print(f'Z is equal to {z}')

Output:

Z is equal to 3.0

400

What will the following code output:

Input:

50

Code:

 

try:

    eaten_chips = int(input())

    if eaten_chips < 0:

        raise ValueError('Kevin was seen eating chips')

    left_over_chips = 250 - eaten_chips

    print(f'Left over chips: {left_over_chips}')

except ValueError as excpt:

    print(f'Error: {excpt}')

output:

Left over chips: 200

500

What will the following code output:

Input:

bluesky

greengrass

valid_user_name = False

while valid_user_name == False:

    try:

        password = input()

        if len(valid_user_name) < 10:

            raise ValueError('Invalid')

        valid_user_name = True

        print('Good Name')

    except ValueError as excpt:

        print(f'Error: {excpt}')

Output:

Error: Invalid

Good Name