Use the definition of logarithmic function to evaluate each logarithmic at the indicated value of x. f(x) = log(subscript 2)x x=32
f(32) = log(subscript 2)32 = 5 because 2^5=32
Solve. e^x=7
x=ln7
x= 1.9459
Use the definition of logarithmic function to evaluate each logarithmic at the indicated value of x. f(x) = logx, x=1/100.
f(1/100)= log1/100=-2
e^x +5=60 Solve.
x=ln55
x=4.007
Use the graph of f to describe the transformation that yields the graph of the function. f(x)= (7/2)^x, g(x)= -(7/2)^(x-6)
Reflect the graph of f in the x-axis and shift six units to the right.
Evaluate the function f(x) = logx when x=-2
No solution, no real number power to which 10 can be raised to obtain -2.
2(3^(2t-5))-4=11 Solve.
t=3.417
True or False, the line y=-2 is an asymptote for the graph of f(x) = 10^x-2. Justify your answer.
true because it will go left until for negative infinity, but it will get so close to -2 but never touch, making -2 an asymptote.
A total of 12000 is invested at an annual interest rate 9%. Find the balance after 5 years if it is compounded continuously. Use the formula A=Pe^(rt)
=12,000e^(0.09(5)) =18,819.75
Solve log(x^2 - 6) = log10.
x^2 -6 = 10
x^2 = 16
x= plus or minus 4
Find the Domain, x-intercept, and vertical asymptote of the logarithmic function and describe the graph. g(x) = ln(-x)
Domain: (-infinity, 0) x-intercept: (-1,0) Vertical asymptote: x=0 The Graph will come the upper left quadrant and pass through (-1,0) and then travel close the x=0 till infinity without touching it.
With the given formula for compounding per year: A=P(1+r/n)^(nt). A total of 12000 is invested at an annual interest rate 9%. Find the balance after 5 years if it is compounded quarterly.
A=P(1+r/n)^(nt) = 12000(1+ 0.09/4)^(4(5)) approximately equal to 18,726.11
ln((x^2)-2) = ln23
Solve for x.
x=-5,5
logx - 2logy + 3logz. condense to a single quantity.
logx/logy^2 + logz^3 =(logx/logy^2)( logz^3) =log((xz^3)/y^2)