What would be the transformation of 3x+1
It translated one unit up
Evaluate the function given by f(x) = ex when x=-2
f(-2) = e^-2 = 0.13533553
Use the definition of logarithmic function to evaluate each logarithmic at the indicated value of x. f(x) = log 2x if x = 32
f(32) = log232 = 5 because 25 = 32
5
Use the changing base formula to solve log4 25
log 25/log 4
2.3219
Solve. ex=7
lnex = ln7 x=ln7
h(x) = e-x x = 3/4
0.472
Use the definition of logarithmic function to evaluate each logarithmic at the indicated value of x. f(x) = logx, x=1/100.
f(1/100)= log1/100=-2 -2
use the natural logarithms changing base formula to solve log 2 12.
ln 12/ln 2 =3.5850
ex +5 = 60 Solve.
ex=55
lne^x = ln55 x=ln55 = 4.007
Use the graph of f to describe the transformation that yields the graph of the function. f(x)= (7/2)x, g(x)= -(7/2)-x+6
Reflect the graph of f in the x-axis and y-axis and shift six units to the right.
f(x) = 5000e0.06x x=6
7166.647
evaluate for the function f(x) = logx x=-2
No solution, no real number power to which 10 can be raised to obtain -2.
Use the properties of logarithms to write the logarithms in terms of ln2 and ln3 : ln2/27
=ln2 - ln27 =ln2 - ln3^3 =ln2-3ln3
2(32t-5) - 4 = 11 Solve.
t = 3.417
2(32t-5)=15
32t-5= 15/2 log332t-5=log3 15/2
2t-5 =log37.5 t =5/2 + 1/2 log3 7.5
True or False, the line y= -2 is an asymptote for the graph of f(x) = 10x - 2. Justify your answer.
true because it will go left until for negative infinity, but it will get so close to -2 but never touch, making -2 an asymptote.
A total of 12000 is invested at an annual interest rate 9%. Find the balance after 5 years if it is compounded. Use the formula A=Pe^rt
=12,000e0.09(5) =18,819.75
Use the one to one property to solve log(x2 - 6) = log10.
x2 -6 = 10 x2 = 16 x= +/- 4
Condense the expression to the logarithm of a single quantity. 1/4log3 5x
log3 5x to the fourth root
Solve. 5 + 2lnx =4
x=0.607
5+2lnx=4 2lnx=-1 lnx=-1/2 e^lnx=e^-1/2 x=e^-1/2
Find the Domain, x-intercept, and vertical asymptote of the logarithmic function and describe the graph. g(x) = ln(-x)
Domain: (-infinity, 0) x-intercept: (-1,0) Vertical asymptote: x=0 The Graph will come the upper left quadrant and pass through (-1,0) and then travel close the x=0 till infinity without touching it.
With the given formula for compounding per year: A=P(1+r/n)nt. A total of 12000 is invested at an annual interest rate 9%. Find the balance after 5 years if it is compounded. Find the quarterly compounding by setting n=4.
A=P(1+r/n)nt = 12000(1+ 0.09/4)4(5) approximately equal to 18,726.11
ln((x2) -2 = ln 23
Use the One to One property to solve for x.
x=-5,5
logx - 2logy + 3logz. condense to a single quantity.
logxz3/y2
You have deposited $500 in account that pays 6.75% interest, compounded continuously. how long will it take to double? Use the formula A=Pert
t=10.27
A=500e=1000 e0.0675t= 2 lne0.0675t=ln2 0.0675t=ln2 t=ln2/0.0675