6.1 Exponential Growth/Decay Functions
6.2 The Natural Base e
6.3 Logarithms
6.5 Properties of Logarithms
6.6 Solving Exponential and Logarithmic Equations
100

Determine whether the function represents exponential growth or decay: 

y=1/5*2^x

Exponential Growth 

100

What is the approximate value of e?

~2.718

100

What is a logarithm?

An exponent!

100

True or False (and explain):

log_b m+log_b n = log_b(m + n)

False

100

log(5x-8)=log(3x-4)

x=2

200

Graph: 

y=4*(1/2)^x

200

Simplify: 

e^7/e^5

e^2

200

Evaluate: 

log_5 1

0

200

True or False (and explain):

log_b m - log_b n = log_b m/(log_b n)

False

200

log_3 (2x-5)=2

x=7

300

You bought a car new for $30,000. The value of your car decays exponentially by 10% each year. Write an equation to model the car's value after t years.

V(t) = 30,000(0.9)^t

300

Determine whether the function is exponential growth or decay: 

y=6e^(-6x)

Exponential Decay

300

Evaluate: 

ln(1/e)

-1

300

Expand: 

log_8 3x^2y

log_8 3 + 2log_8 x + log_8 y

300

5^(x − 3) = 25^(x − 5)

x=7

400

The average price for a gallon of milk was $1.03 in 1990. Since then, the price has increased approximately 2.7% each year. Find the year in which the cost of a gallon of milk was $1.27.

1998

400

Simplify: 

(e^-8e^6)/e^4

1/e^6

400

Evaluate: 

log_100(1/10)

-1/2

400

Condense: 

ln40+ln3 - ln10

ln 12

400

Solve for x. 

log_2 x + log_2(x − 2) = 3

x=4

500

You deposit $1,500 into an account that pays 7% annual interest. Find the balance (to the nearest hundredth) after 10 years when the interest is compounded monthly.

$3,014.49

500

An account earns 3% annual interest compounded continuously. Find the principal (to the nearest hundredth) when the balance is $100 after 10 years.

$74.08

500

Find the inverse of: 

y=log(x-7)

y=10^x+7

500

Expand: 

log_7 ((a^3b\sqrtc)/(2d))

3log_7 a + log_7 b + 1/2 log_7 c - log_7 2 - log_7 d 

or

3log_7 a + log_7 b + 1/2 log_7 c - (log_7 2 + log_7 d)

500

Solve for x. Leave your answer in terms of a logarithm.

5(7)^(5x)-2 = 58

log_7 12/5

or

log12/(5log7)

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