Rates & Factors
Investing
RU(L)ES!
RUL(E)S!
RULE(S)!
100

Does the following equation model exponential growth or decay?

y=300(1.001)^t

Growth

100

Which is the best investment for $1000?

A) 5% interest compounded annually

B) 5% interest compounded continuously

C) 5% interest compounded monthly

B) 5% interest compounded continuously

100

What is the value of t (time) in the following problem?


"A man invested $2000 in a savings account when his first grandchild was born. The account held $4100 on the grandchild's eighteenth birthday. If the interest was compounded monthly, what was the annual interest rate?"

t=18

100

A savings account has $1,500 invested at an annual interest rate of 4%, compounded annually. How much money will be in the account after 6 years?

A=1500(1.04)^6

100

Solve (four decimal places):

 ln(2x)-1=1.537 

x=6.3208

200

If the growth factor is 1.57, what is the percentage of increase or decrease?

+57%

200

"You invest $12000 in an account with a 7.3% interest rate, compounded monthly. How long will it take for you to have $20000 in the account?"


What value would you put in place of ?:

20000=12000(1+(? )/12)^(12t)


.073

200

What is the INITIAL VALUE in the following word problem?


After driving it for three years, the car your parents bought you is now worth only $2130. If your parents paid $6500 for it, by how much did the value of the car depreciate each year?

P=6500

200

A car is currently worth $18,000, but the value depreciates by 11% each year. How long will it take for the car to reach a value below $10,000?

10000=18000(1-.11)^t

200

Solve (round to 2 decimals):

200000=180000(1.17)^t

t=0.67

300

If the decay factor is 0.9, what is the percentage of increase or decrease?

-10%

300

"You invest $12000 in an account with a 6.5% interest rate, compounded quarterly. How long will it take for you to have $20000 in the account?"


What value would you put in place of ?:

20000=1200(1+.065/?)^(?t)

4

300

What is the value of n in the following problem?

"After high school you plan to rent an apartment. The place you plan to live has a great starting price at only $500 a month, but the rent will increase by 20% each quarter. How much will your rent be at the end of two years?"

"Each quarter" means n=4 

300

An investment grows to $9,400 after 10 years at an annual interest rate of 3.2%, compounded quarterly.
What was the original amount invested?

9400=P(1+.032/4)^(4*10)

300

Solve (four decimal places):

1600=1100(1+r)^5

r=.0778

**BONUS 100 POINTS: 7.78%**

400

What is the growth factor for a value that triples annually?

3

400

"You invest $12000 in an account with a 16% interest rate, compounded annually. How long will it take for your money to double?"


What value would you put in place of ?:

?=12000(1.16 )^(t)

24000

400

What is the value of r in the following problem?

The population of wild polar bears in a certain region of Alaska has been decreasing by 20% each year for the past decade. If there are now only 30 polar bears in the region, how many polar bears were there 10 years ago?

r=-0.20

400

A piece of equipment was purchased 4 years ago for $6,000 and is now worth $3,960. Find the annual rate of depreciation.

3960=6000(1-r)^4

400

Solve (four decimals):

0.758=0.983e^(k*100)

k=-.0026

500

What is the growth or decay factor for a value that decreases by 4.3% annually?

0.957

500

"You invest $12000 in an account with a 4% interest rate, compounded continuously. How long will it take for you to have $20000 in the account?"


Write the full equation you would use to solve this problem.

20000=12000e^(.04t)

500

What is the TIME (t) value in the following problem?


"In 1916, California established a state minimum wage of 16ยข per hour. If the minimum wage today is $16.50, what was the average annual percent increase?

t=109 years

500

A scientist is studying bacteria that multiplies continuously. The population of a culture increases from 220 cells to 500 cells in 9 hours. What is the growth constant of the bacteria?

500=220e^(9k

500

Solve (round to two decimals):

21400=P(1+.14/12)^(12*5)

P=10670.07

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