Growth or Decay?
Applying Exponential Equations
Random
Logs
100

Is the following growth or decay: f(x) = 2(0.09)^x

decay

100
The population in the town of Huntersville is presently 38,300. The town grows at an annual rate of 1.2%. Find the number population of the town after 9 years.
Approximately 42,640 people
100
Write an exponential growth function to model the situation. A population of 422,000 increases by 12% each year.
What is f(x) = 422,000(1.12)^x
100

Solve the following, Round to the nearest hundredth

10= 50


log50 or x = 1.70

200
Is the following growth or decay: f(x)=100*(0.5)^x
What is decay
200
$1,200 is invested at an annual rate of 3.2%. How much money will the account have after 12 years?
$1751.21
200
The population of Baconburg starts off at 20,000, and grows by 13% each year. Write an exponential growth model and find the population after 10 years.
What is f(10) = 20,000(1.13)^10 and population of 67,891
200

Solve the following, round your answer the nearest hundredth

6 * 10x = 48

log8 or x = 0.90

300
Is the following growth or decay: f(x)= 100*(1.4)^x
What is growth
300
The population in the town of Deersburgh is presently 42,500. The town has been growing at a steady rate of 2.7%. What will the population of the town be in 5 years?
Approximately 42, 499 People
300

1) Write the following in exponential form: log5x=2

2) then solve

52=x

x=25

300

Solve the following, round your answer the nearest hundredth

3 * 5x = 15

x = 1

400
Is the following growth or decay: f(x) = 7 (0.94)^x
What is decay
400

The value of a stock when purchased is $10 a share. However, over the past 5 days the price went down at a constant rate of 4%. How much is the stock worth now?

$8.15

400

Write the following in exponential form:

log800 = x

10x = 800

400

Solve the following, round your answer the nearest hundredth

2* 10x = 80

log40 or 1.60

500
Is the following growth or decay: f(x) = -350 (1.25)^x
What is growth
500

The value of a car was $22,000 when it was purchased. They car depreciates at a rate of 19% per month. How much will the car be worth in 2 years?

$139.97

500

  1. Express the toy’s value t , in dollars, as a function of time w, in weeks, after purchase.

t(w) = 5(2)1t/3

500

Solve + round answer to nearest hundredth: 

6 * 10x = 0.60

x =log 0.1

OR x = -1

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