Formulate the Formula
The population of a town grows by 5% annually. If the population was 15,000 people initially, write an equation to represent the population after t years.
What is ... P(t) = 15000 (1.05)t
The population in the town of Huntersville is presently 38,300. The town grows at an annual rate of 1.2%. Find the number population of the town after 9 years.
What is... Approximately 42,640 people
Use y = 250(1.2)x What is the initial value?
What is... 250
Solve: 53-2x = 5-x
What is ... x = 3
Simplify (6z-2)/(12z-1)
what is... (1)/(2z1)
A car depreciates at a rate of 12% per year. If the car's initial value is $18,000, write an equation for the car's value after t years.
What is... V(t)=18000(0.88)t
$1,200 is invested at an annual rate of 3.2%. How much money will the account have after 12 years?
What is... $1751.21
Use y = 250(1.2)x What is the growth factor?
What is... 1.2
Solve: 31-2x = 243
What is... x = -2
Re-write 645/6
What is... x = 32
The New York Mets sign a new player for $8,000,000 and his salary goes up by 3% every year. Write the function that models the amount of money the player makes as time goes on.
What is ... F(x) = $8,000,000(1.03)x
The population in the town of Deersburgh is presently 42,500. The town has been growing at a steady rate of 2.7%. What will the population of the town be in 5 years?
What is... Approximately 42, 499 People
Use y = 250(1.2)x What is the growth rate?
What is ... 20%
Solve: (1/5)-3x = 625
What is ... x = 4/3
Re-write 25(-3/2)
what is... 1/125
Using the ordered pairs:
(0,150),(1,120)(2,96)(3,76.8)(4,61.44)(5,49.15)
What is ... P(x) = 150 (0.8)x
A car depreciates at a rate of 19% per year. After 8 years, the car is worth $4076.64. How much was the car worth when purchased?
What is ... $22,000
y = 9.8(.35)x What is the decay factor?
What is... 0.35
Solve: 16x+3=643x+6
what is ... x = -12/7
Simplify (100m17n13)/(5m12n19)
what is... (20m5)/(1n6)
You invest $2,000 in an account that compounds interest quarterly at a rate of 5%. Write an equation that represents the amount of money in the account after t years
What is... A = 2,000(1 +(0.05/4))4t
A radioactive element decays at a rate of 5% annually. There are 40 grams of the substance present. When will the amount of the substance drop to below 20 grams (to the nearest year)?
What is... Approximately 14 years
y = 9.8(0.35)x What is the decay rate?
What is... 65%
Solve: 20-6x+6 = 55
What is... x = -1/3
Simplify (-x3y4)3(-5x2y)2
what is... -25x13y14