Scientific/standard Notation
Write this number in scientific notation: 2500
2.5x103
John starts with $40 and doubles his money each money. Write an equation to describe this situation.
y=40(2)^x
An iceberg is melting by half each day. The iceberg starts at 300 feet tall. Write an equation to describe this situation.
y=300(1/2)^x
Simplify the following
x^5 *x^4
x^(5+4)
x^9
Simplify the following
(x^6)^3
x^(6*3)
x^18
Write this number in standard notation: -7.05x105
-705,000
Alexis has $5 and triples her money every week. How much money will she have in 4 weeks?
y=5(3)^x
x=4
$405
A tree weighs 20 tons. It decays by half each year. How much will the tree weigh in 3 years?
y=20(1/2)^x
x=3
2.5 tons
Simplify the following
x^7/x^-3
x^(7--3)
x^10
Simplify the following
a^8b^0c^4
a^8(1)c^4
a^8c^4
Write this number in scientific notation: 0.000026
2.6x10-5
Bacteria doubles every day. There are 15 bacteria at the start. When will there be 15,360 bacteria?
10 days
Ms. Hammell has 400 pencils and gives away a three quarters of her pencils each month. How many pencils will she have in 4 months?
y=400(1/4)^x
x=4
1 pencil
Simplify the following
4x^3 * 3x^5
4*3x^(3+5)
12x^8
Simplify the following
(2x^4)^3
2^3x^(4*3)
8x^12
Simplify and put answer in scientific notation: (2.5x103 ) x (6.3x105)
1.575x109
The population of a town is 5000 and increasing at 4% each year. Find the population in 5 years.
y=5000(1.04)^x
x=5
6083 people
The elephant population is decreasing by 2% each year. The current population is 50,000. Find the population is 10 years.
y=50000(0.98)^x
x=10
40,853 elephants
Simplify the following
(x^5y^6z^9)/(x^3yz^4)
x^(5-3)y^(6-1)z^(9-4)
x^2y^5z^5
Simplify the following.
(6a^4b^6)^2
6^2a^(4*2)b^(6*2)
36a^8b^12
Simplify and put answer in scientific notation: (6.2x104)/(3.1x108)
2x10-4
You have $80 and your money is increasing at 1.2% every year. When will you have over $100?
y=80(1.012)^x
y>100
19 years
You buy a new car for $25,000. The car decreases in value by 5% per year. When will the car be worth less than $10,000?
y=25000(0.95)^x
y<10,000
18 years
Simplify the following. NO NEGATIVE EXPONENTS
(14a^6bc^2)/(2a^3b^5c^3)
7a^(6-3)b^(1-5)c^(2-3)
7a^3b^-4c^-1
(7a^3)/(b^4c)
Simplify the following. NO NEGATIVE EXPONENTS
(a^9b^6c^0)^-3
a^(9*-3)b^(6*-3)c^(0*-3)
a^-27b^-18c^0
1/(a^27b^18)