By GCF Method, factor
2x2 + 10x - 16
2(x2 + 5x - 8)
Factor the trinomial:
x2 + 13x + 12
(x+12)(x+1)
Factor the trinomial:
6x2 + 17x + 5
(2x + 5)(3x + 1)
Factor the special trinomial:
x2 + 10x + 25
(x+5)2
Is this factored completely: 3x2(x2 + 9). Why or why not?
Yes, there are no more common factors between x2 and 9.
By GCF Method, factor
12x2 + 8x - 20
–4(3x2 – 2x + 5)
Factor the trinomial:
x2 − 13x + 36
(x-9)(x-4)
Factor the trinomial completely:
3x2 + 13x +4
(3x+1)(x+4)
Factor the special trinomial:
9x2 + 6x + 1
(3x+1)2
Factor completely:
2x2+6x-56
2(x-4)(x+7)
By GCF Method, factor
5x3 + 2x2 + x
x(5x2 + 2x + 1)
Factor the trinomial:
x2 + 4x − 45
(x+9)(x-5)
Factor the trinomial:
6x2 + 11x + 3
(2x + 3)(3x + 1)
Factor this special binomial:
x2 - 16
(x-4)(x+4)
Factor completely:
2p5 + 10p4 - 12p3
2p3(p - 1)(p + 6)
By GCF Method, factor
2x4 - 16x3 + 4x
2x(x3 - 8x2 + 2)
Factor the trinomial:
x2 − 16x + 48
(x-12)(x-4)
Factor the trinomial:
6x2 + 7x - 3
(2x + 3)(3x - 1)
Is this binomial factorable? If so do it, if not write "prime": 1 - 4x2
(1 + 2x)(1 - 2x)
Factor Completely:
9x6 + 30x5 + 24x4
3x4(x + 2)(3x + 4)
By GCF Method, factor
8x2y −12x3y2
4x2y(2 - 3xy)
Factor the trinomial:
2x2 + 2x − 4
2(x+2)(x-1)
Factor the trinomial:
3x2 - 2x - 8
(3x + 4)(x - 2)
Factor this special trinomial: 4x2 + 20x + 25
(2x+5)2
Factor completely:
3x2 – 30x + 75
3(x – 5)2