2x2-4xy+6y
2x(x-2y+6y)
x2+4x+4
(x+2)(x+2)
x2-1
(x+1)(x-1)
x3-2x2+2x-4
x2(x-2)+2(x-2)
(x2+2)(x-2)
3x-4x = 9
-x = 9
x = -9
Factor the GCF:
25x5y-15y
5y(5x4-3)
x2+x-56
(x+8)(x-7)
4x2-25
(2x-5)(2x+5)
5x3-4x2-25x+20
x2(5x-4)-5(5x+4)
(x2-5)(5x-4)
9x2-3x = 0
3x(3x-1)=0
3x=0 or 3x - 1= 0
x=0, x= 1/3
Factor the GCF
2x-3y-7z+9
1(2x-3y-7z+9)
-2x2-12x-16
-2(x2+6x+8)
-2(x+4)(x+2)
-81x2-121
-(81x2+121)
Cannot factors since it is not a difference of squares.
9x3-9x2-4x+4
9x2(x-1)-4(x-1)
(x-1)(9x2-4)
(x+1)(3x-2)(3x+2)
x2-1x-56=0
(x-8)(x+7)=0
x-8=0, x+7=0
x=8, x=-7
Factor the GCF
-4x4y3z2 - 24xy3z +32x4y3z
-4xy3z(x3z + 6 - 8x3)
x3-12x2+27x
x(x2-12x+27)
x(x-9)(x-3)
-144x2y4+25z9
-(144x2y4-25z9)
-(12xy2 - 5z3)(12xy2+5z3)
x4+3x3-3x2-9x
x(x3+3x2-3x-9)
x(x2(x+3)-3(x+3))
x(x+3)(x2-3)
16x3-4x2-36x+9=0
4x2(4x-1)-9(4x-1) =0
(4x2-9)(4x-1)=0
(2x-3)(2x+3)(4x-1)=0
x=2/3, x=-2/3, x=1/4
A rectangle has a length of x-5 feet and a width of x-2. Find the dimensions of the rectangle given that the area is equal to 40.
40 = x2-2x-5x+10
0 = x2-7x-30
0 = (x-10)(x+3)
x=10, x=-3
x=10,
length: 10-5 =5. width: 10-2= 8