2x2 + 10x - 16
2(x2 + 5x - 8)
x2 + 13x + 12
(x+12)(x+1)
6x2 - 21x - 9
3(2x2 - 7x - 3)
x2 - 25
(x-5)(x+5)
Is this factored completely:
3x2(x2 + 9). Why or why not?
Yes, there are no more common factors between x2 + 9 is not facotrable.
2x2 + 19x - 10
2x4 - 16x3 + 2x
2x(x3 - 8x2 + 1)
2x2 + 2x - 4
2(x+2)(x-1)
6x3 + 7x2 - 3x
x(2x + 3)(3x - 1)
3x2 - 6x - 9
3(x -3)(x + 2)
x3 + x2 + x
x(x2 + x + 1)
2x2 + 8x − 90
2(x+9)(x-5)
-12x2 + 8x - 20
–4(3x2 – 2x + 5)
2x2 - 32
2(x-4)(x+4)
2p5 + 10p4 - 12p3
2p3(p - 1)(p + 6)
14x2 - 15x + 4
(7x - 4)(2x - 1)
x2 − 13x + 36
(x-9)(x-4)
3x3y + x2y2
x2y(3x + y)
x2 - 11x + 30
(x - 5)(x - 6)
9x6 + 30x5 + 24x4
3x4(3x + 4)(x + 2)
8x2y −12x3y2
4x2y(2 - 3xy)
x2 − 20x − 125
(x-25)(x+5)
6x2 + 36x + 48
6(x + 4)(x + 2)
Factor Completely:
8x2 + 2x - 3
(2x - 1)(4x + 3)
x2 − 16x + 48
(x-12)(x-4)