Solving Logs and Exponents
log100,000
5
log(base 4)(x)=7
4^7=x
log10+log100
3
log(base x)(71)=301
x^301=71
$12,000 is invested into a company that earns a 3.2% interest compounded continuously. How many years will it take to get to $18,000.
12.67 years
10^1=x
log(x)=1
3log(2x-1)=10
x=1077
P^x=y
log(base P)(y)=x
f(x)=ln(2x-3)+1
x= 1/2e + 3/2
log(base 12)(x)=1/60
12^1/60=x