imaginary #
x^4+6x^2=27
x=3,iā3
f(x)=x^3+2x^2-9x-18
x=-2,-3,3
(a+b)(a-b)
a^2-b^2
(3x+4)(3x-4)
9x^2-16
x^2-6x-27=0
x=9.3
x^2+6x+8=0
x=-2,-4
(7j^3-2)+(5j^3-j-3)
12j^3-j-5
(-x^2+x-4)-(3x^2-8x-2)
-4x^2+9x-2
x=-11,11
x^4-121x^2=0
x^5-8x^4+7x^3=0
x=0,7,1
(3m^5+1)+(9m^5+3m-2)
12m^5+3m-1
(-2x^3=x)-(7x-3-7x^3)
5x^3-6x+3
x^3-3x^2-54x=0
x=0,9,-6
x^4+12x^2=64
x=-2,2,4i,-4i
(3x^2-2x+1)+(-x^2+3x+1)
2x^2+x+2
(5x^3+3x^2+5)-(7x^3-9x^2+8x-5)
-2x^3+12x^2-8x+10
0=x^3+2x^2+5x+10
x=-2, Iā5,-1ā5
7x^2+12x-27=0
x=-3,9/7
(2x-5)(5x^2=4x=7)
10x^3-17^2-6x-35
(-2x^2y)(5xy^7)
-10x^3y^8