Test 1
Test 2
Test 3
Test 4
Test 5
100

How many sig figs are in 0.00009805

4

100
Charge of an electron

-1

100

What is the molar mass of Oxygen

12g

100

What kind of reaction type is this?

A + B = AB

Combination

100

What do acids and bases taste like? 

Acids= sour

Bases=bitter

200

What is the scientific notation .00849 ?

8.49 x 10^-3

200

What element is a halogen in the fifth row?

Iodine

200

What is the mass percent of Carbon in CO2?

27%

C=12

O=16(2)=32

CO2=44

200

A reaction needs 2578J to be completed. Is it exothermic or endothermic?

Endothermic

200

What could increase the rate of a reaction?

Increase temperature

Increase concentration

Add a catalyst

300

What is the volume of a substance with a density of 1.28g/mL and a mass of 3.85g.

3.01 mL 

300

What is the name for N3S2?

Trinitrogen Disulfide

300

What kind of shape does PH3 have?

Bent

P-5 ve

H-3 ve

PH3-8ve 

300

What are the products of a combustion reaction?

CO2 and H2O

300

What is the name of this acid?

H2SO4

Sulfuric Acid

400

A sample of Au (Specific Heat is 0.129 𝐽/gC) absorbs 5557 J. The temperature increase from 15.1 oC to 65.0oC. Determine the mass of the sample.

∆E = SH mass ∆T

∆T= Tfinal - Tinitial=65 - 15.1=49.9oC

5557J=(0.129j/gC)(X)(49.9C)

860g=mass


400

Calculate the amount of energy in Joules found in a light sources which has the wavelength of 836 nanometers. Provide the correct number of sig figs.

h=6.626 x 10-34J(sec)

c=3 x 108m/sec 

836m x 1 𝑚/109 𝑛𝑚 =836 x 10-9

E=hc/λ 

E=(6.626 x 10-34J(sec))(3 x 108m/sec)/836 x 10-9

E=2.38 X 10-19

400

What is the number of grams in 8.3 mols of NH4Cl?

(8.3mols/1 NH4Cl)(53.491g/1mol)=440 g NH4Cl

400

Determine the milliliters of a 1.45 M TiCl4 solution are needed to make 105 mL of a 0.219 M TiCl4 solution.

MV=MV

(1.45M)(V) = (0.219M)(105mL)

V=(0.219M)(105mL)/(1.45M)

V=15.9 mL

400

A) On which side of a battery do these occur?

Oxidation 

Electron flow

B)What kind of reaction is happening to Iron in the forward reaction? 

2Fe(s) + 3Cl2(g) --> 2FeCl3(s)



A) Oxidation=the side with the anode

Electron Flow=the side with the cathode

B) 2Fe(s) + 3Cl2(g) --> 2FeCl3(s)

      0             0            +3 -1

Oxidation - loss of electrons

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