Logarithms/Exponents
Solve 2x = 3
x=ln(3)/ln(2)
You receive $5000 to invest in a bank account paying 4.5% interest compounded annually. If you leave the money in there for 15 years, how much will you have?
$9676.41
How much will you have at the end of 5 years if you leave $610 in an account with 8.4% interest compounded continuously?
$928.40
Find the inverse of
f(x) = 2x-4
f^(-1)(x)=1/2x+2
Solve 2x-1 = 17
x=(ln(17)+ln(2))/ln(2)
You receive $200 to invest in a bank account paying 12.1% interest compounded monthly. If you leave the money in there for 5 years, how much will you have?
$365.14
How much should you invest at 4.8% compounded continuously to have $5000 in 2 years.
$4542.32
find f(g(x)) when
f(x) = 3x-2 : g(x) = x2
f(g(x))=3x^2-2
Solve
log_2(x-1)+log_2(x)=1
x=2
What amount must you invest in a bank account paying 11.1% interest compounded annually if you wish to have $10000 after 8 years?
$4308.12
How much should you invest at 9% compounded continuously to have $10000 in 8 years.
20544.33
Are these functions inverses?
f(x) = x^2-1 :&: g(x) = sqrt(x+1
Yes
Solve
log(x^2+1)-log(2)=log(13)
x=5,-5
If you invest $50 in a bank account paying 12% interest compounded quarterly, how long does it take if you wish to have $200?
t = 11.72 years
How long should you invest $1000 at 4.8% compounded continuously to have $5000?
t = 33.53 years
Find the inverse of
f(x) = 1/(4x
f(x) = 1/(4x
Solve
2^x=5^(x-1)
x=ln(5)/(ln(5)-ln(2))
If you invest $322 in a bank account paying 2.2% interest compounded daily, how long does it take if you wish to have $400?
t= 9.86 years
What is the rate of the account giving you $3000 at the end of 6 years when you initially invested $1678?
r=.096 or r=9.6%
Find f(g(h(x))) if
f(x) = 2x+1:&: g(x) = x^2+1 :&: h(x)=x+1
f(g(h(x)))= 2x^2+4x+5