Percent and rate
Recursion
Compound Interest
Depreciation
Hodge Podge
100

The percent equivalent of 1/4.

25% 

100

The mathematical display for the starting value

V0

100

The number of periods for calculating interest on a savings account that is compounded monthly for two years.

24 periods

100

The name for the decrease in value of an asset for tax purposes.

depreciation

100

The type of account that a scholarship fund is funded from, where the balance remains the same, and the payment is the same as the interest earned

perpetuity

200

The decimal equivalent to 7.5%.

0.075

200

The recursion relation for the scenario: an investment of $500, with simple interest rate of 2.2%

Vo=500, Vn+1=V+ 11

200

The value of an account that starts with $300 and is compounded monthly at 3.5% p.a. for one year.

300 x (1+ 3.5/100 x 12)^12

$310.67 

200

The type of depreciation where value decreases depending on how much the asset has been used

Unit cost depreciation

200

If the interest made in one month was $141.25 and the previous balance was $12000, what is the interest rate per month?

141.25/12000  x 100 = 1.18%

300

The R value when there is flat rate depreciation of 8.5%

R = 0.915 (1.0-0.085)

300

the recursion relation for a car that was purchased for $18,000 and depreciates at a flat rate of $550 per year

Vo=18,000   Vn+1=Vn - 550

300

The number of periods when interest is compounded quarterly for five years.

20

300

Description for when an asset has been depreciated to the point where it is no longer considered valuable to the company for tax purposes.

scrap value

300

An investment that gains interest and then a payment is taken out each month, continuing until there is no money left.

Annuity

400

the monthly interest rate when the rate is 12.5% p.a compounding quarterly

12.5/4 = 3.125% per month

400

The R value for the recurrence relation where $4750 is borrowed at an annual rate of 3.75% p.a, compounding quarterly.

R = 1.009375

400

The interest charged on $567, compounded monthly, when the annual interest rate is 15%.

567 x (15/100 x 12)

$7.0875 = $7.09

400

A method of reducing the value of an asset where it is uniformly reduced each year until it is not worth anything.

Flat rate depreciation

400

Which is a better bank rate option for an investment account:

Option 1: 4.56% pa, compounding monthly

Option 2: 4.50% pa, compounding fortnightly

Option 1: r(eff)=4.66%

Option 2 r(eff) = 4.60%

So option 1 as its an investment

500

The effective interest rate when the bank advertises 4.75% p.a, compounding fortnightly

r(eff) = 4.86%

500

the annual interest rate in the following recurrence relation, where compounding occurs fortnightly: 

Vo=10,000    Vn+1= 1.000875Vn -380

.000875 x 26 x 100

r=2.275%

500

The value of the following reducing balance loan after 3 months, when it compounds monthly:

Vo= 245,000     Vn+1=1.000245xVn - 980

$242663.71

500

An R value of 0.895 tells us the depreciation rate as a percentage is....

r=10.5%

500

Balance at the end of two months for a starting amount of $1590 with interest compounded monthly at 19% p.a. and monthly payments of $160.

 $1318.22 

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