Domain / Range
AOS, Vertex, Max, Min, etc.
Inverse
Write an Equation
Completing the Sqaure
100

Domain of y = x2

(-∞, ∞)

100

Axis of Symmetry of y=−2(x+1)2+8

x=-1

100

Inverse of: f(x)=3x+5

f-1(x)= x - 5 / 3

100

Write the equation of a parabola with:

vertex (2,−4) , a=3

y=3(x−2)2−4

100

y=x2+6x+5

y=(x+3)2−4

200

Domain / Range of: x2+y2=16

Domain[-4, 4]

Range[-4, 4]

200

Max / Min of: y=3(x−3)2−6

  • Opens upward → has a minimum
  • Minimum value: −6
200

Inverse of f(x) = x2 + 8 

f-1(x) = +- √x-8

200

A parabola has vertex (1,2) and passes through point (3,10). Write an equation. 

y=2(x−1)2+2

200

y=2x2+8x+3

y=2(x+2)2−5

300

Domain / Range of: y=−√(x+2)+4

  • Domain: x≥−2
  • Range: y≤4
300

Vertex of y=-2(x+4)2+5

(-4, 5)

300

What is the 3-step process for finding the inverse of a function?

Write the inverse as y =

Swap x and y

Solve for y 


300

A parabola has vertex (−2,3) and passes through (0,11). Write the equation.

y=2(x+2)^2+3

300

y=−3x2−12x−7

y=−3(x+2)2+5

400

Range of y=−2(x−1)2+8

Range: y≤8

400

End Behaviours of -3√(2x+4) +2. 

x -> ∞ y -> -∞

X -> -2+ y -> 2

400

Will f-1(x) = +- √x-8 have EB's? Why / Why not? 

No. Fails VLT. Not a function

400

Write an equation: A reflection in y axis, vertical stretch by 2, horizontal shrink by 1/3, horizontal shift left 6, vertical shift up 12

y=2(-3(x+6))2+12

400

y=−2x2+8x+5

y=−2(x−2)2+13

500

Domain / Range of: y=−3x2+12

  • Domain: (−∞,∞)
  • Range: y≤12
500

DOP, Vertex, End Behaviours, AOS, Max  / Min of: y=−2x2+12x−5

y=−2(x−3)2+13

Vertex: (3,13)

Down

AOS: x=3

So it has a maximum value of 13 when x = 3.

EB: As x→∞,  y→−∞  , As x→−∞,  y→−∞x

500

Find the inverse of: f(x)=(x−1)2

f-1(x)= √(x) +1 

500

Write equation; Reflection in x , y axis, VC by 1/2, HC by 1/2, H. shift right 10 units, vertical shift down 7 units

y = -1/2 ( -2 (x-10))2-7

500

y = -2x2 - 3x + 7

y = -2 (x+3/4)2+65/8

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