The Original Function is: f(x)=|x|, if you subtract one to get f(x)=-|x|-1, what happens to the graph?
Reflect over the x axis, and then shifts down by 1.
The Original Function is: f(x)=x^2, your new function is f(X)=(x-1)^2-3. What happens to your graph?
The graph shifts right 1 down 3.
The Original Function is: f(x)=|x|, if your new function is f(x)=3|x-1|. How did the graph change?
The graph shifts to the right one, and IS STRETCHED VERTICALLY (narrower)
The Original Function is: f(x)=x^2, your new function is f(X)=-(x-4)^2. What happens to your graph?
Reflected over x axis (opens down), then The graph shifts to the right 4 times.
To find the y-intercept of Standard Form you use..
C
The Original Function is: f(x)=|x|, if your new function is f(x)= -1/2|x+1|-4, what happens to your graph?
The graph is flipped over the x axis, compressed vertically (wider), then shifts to the left one, down 4
The Original Function is: f(x)=x^2, your new function is f(X)=1/3(X+5)^2. What happens to your graph?
The graph shifts to the left 5 times. It is also COMPRESSED VERTICALLY
The Original Function is: f(x)=|x|, your new function is f(x)=|3x|, what happens to your graph?
The graph is "compressed" horizontally....
(think about how the graph ACTUALLY looks)
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This is an odd, positive, function: y=ax^3+bx^2+cx+d. What degree is it?
What is third degree?