What do the "1" and "2" represent in the combined gas law equation?
"1" represents the initial condition (starting point) and "2" represents the final condition (ending point).
If a problem has a variable held constant, what are you supposed to when solving the equation?
You should either A) remove the variable from both sides or B) plug the same number in both sides.
Rearrange the combined gas law equation to solve for P1.
P1= (P2V2T1) / (V1T2)
what is the name of the math process used to solve proportions (fractions set equal to one another)?
Cross multiply and divide
Label each value with the correct variable (P, V, or T)
1.86 atm, 4.33 L, 26.5 °C, 285K, and 3.45 mL, 9.5 psi.
atm and psi= Pressure
L and mL= volume
°C and K= temperature
What is the correct version of the combined gas law if temperature is held constant?
P1V1=P2V2
Suppose you have a sample of gas at 303K in a container with a volume of 2L and pressure of 760mmHg. The sample is moved to a temperature of 340 K and the volume increases slightly to 2.1L. What is the pressure of the sample now?
P2= 812 mmHg
Convert both temperatures to Kelvin.
−23.0 °C and 227.0 °C
-23 °C= 250 K
227 °C= 500 K
Which variable (P, V, T) must you always use the same unit when solving the equation.
Temperature; you always have to Kelvin temperature in the equation
You have a flexible container of gas filled to 5.22 L at 292 K. At what temperature would the container increase to be 6.00 L if pressure is held constant?
T2= 336.3 K
You have a sample of gas with a pressure of 1.86 atm, volume of 4.33 L, and temperature of 26.5 °C. If you cool it to 12.7 °C and decrease the volume to 3.45 L, what will the pressure be?
P2= 2.23 atm
Solve the following equation
2.69 = 16.7
x 400
x= 64.4
Label variables P1, P2, V1, V2, T1, and T2.
Suppose you have a sample of gas at 303K in a container with a volume of 2L and pressure of 760mmHg. The sample is moved to a temperature of 340 K and the volume increases slightly to 2.1L. What is the pressure of the sample now?
P1= 760 mmHg, P2= unknown
V1= 2 L, V2= 2.1 L
T1= 303 K, T2= 340 K
A gas occupies 1.56 L at 1.00 atm. What will be the volume of this gas if the pressure becomes 3.00 atm?
V2= 0.520 L
OLD UNIT: Rearrange the following equation to solve for v
D= m / v
v = m / D
Label variables P1, P2, V1, V2, T1, and T2.
You have a flexible container of gas filled to 5.22 L at 292 K. At what temperature would the container increase to be 6.00 L?
P1 and P2 are not stated in the problem, they must be held constant (eliminated).
V1= 5.22 L, V2= 6.00 L, T1= 292 K, T2= unknown
Draw a line graph that represents the following statement:
One variable increases as the other variable decreases
The graph should have a downward slope.