500
A piece of 16-gauge copper wire 42 cm long is bent into the shape of a rectangle whose width is twice its length. Find the dimensions of the rectangle.
the rectangle is 7 centimeters long and 14 centimeters wide.
Since the wire is 42 centimeters long, then the perimeter of the rectangle is 42 centimeters. That is:
2L + 2W = 42
I also know that the width is twice the length, so:
W = 2L
Then:
2L + 2(2L) = 42
2L + 4L = 42
6L = 42
L = 7