Reading/Balancing Chemical Equations
Mg (s) + S (g) --> MgS (s) can be read as
One mole of Magnesium reacts with 1 mole of Sulfur to form 1 mole of Magnesium Sulfide
2 atoms Magnesium react with one atom of Sulfur to form one molecule of Magnesium Sulfide
24.31g Mg react with 32g S to form 56.31g MgS
In the following equation, if 4 moles of Br are used up, how many moles of CaBr2 would you expect to be formed (assume Ca is in excess)
Ca (s) + 2Br (g) ---> CaBr2
2 moles CaBr2
What is the difference between a limiting and excess reagent?
Limiting reactants are completely used up in a reaction, excess reactants are the ones that will have some left over
What is Dr. Bange's kid eating in the first slide of the Ch.3 slideshow
Spaghetti
The substances that are used up are called ___, while the substances being formed are called ____
In the following equation, if 46g of Ca are used up, how many moles of CaBr2 would you expect to be formed (assume Br is in excess)
Ca (s) + 2Br (g) ---> CaBr2
1.15 moles CaBr2
I bought a 8-cup bag of flour, 6 eggs, and 3 cups of milk. A cake calls for 6 cups of flour, 4 eggs, and 3 cups of milk. What is my limiting reagent?
Milk
When balancing chemical reactions, it is important to:
Be sure that no matter is created or destroyed, namely, that there is the same amount of each atom on both sides of the equation
Ca (s) + 2Br (g)--> CaBr2 (s). If 98.3g CaBr2 are formed, how many moles of Br were used up?
0.98 mol Br
2NH3 (g) + CO2 (g) --> (NH2)2CO (aq) + H2O (l).
In this process, 742.4g NH3 is reacted with 1,366.9g CO2.
Which is the limiting reactant?
NH3
CH4 + Cl2 ---> CCl4 + HCl
CH4 + 4Cl2 ---> CCl4 + 4HCl
2Li (s) + 2H2O (l) --> 2LiOH (aq) + H2 (g). How many grams of water are needed to produce 12.45g H2?
225.25g H2O
2NH3 (g) + CO2 (g) --> (NH2)2CO (aq) + H2O (l).
In this process, 742.4g NH3 is reacted with 1,366.9g CO2.
How much (NH2)2CO is produced (in grams)?
1,309.31g (NH2)2CO
Balance the following equation:
C12H22 (s) + O2 (g) --> CO2 (g) + H2O (g)
2C12H22O11 (s) + 35 O2 (g) ----->
24CO2 (g) + 22H2O (g)
C4H8O4 (s) + 4O2 (g) --> 4CO2 (g) + 4H2O (g).
If 444g of C4H8O4 is used up, how much H2O was produced (in grams)?
266.7g H2O
2NH3 (g) + CO2 (g) --> (NH2)2CO (aq) + H2O (l).
In this process, 742.4g NH3 is reacted with 1,366.9g CO2.
How much excess reactant is left (in grams)?