An asteroid of mass m is orbiting a star of mass M with an orbital radius of r. The force of gravitational attraction between the two is F. If the mass of the star were to be changed to 4M, what would the new force of gravity be?
F_2=4F
What is Kepler's first law?
Each planet orbits about the Sun in an Ellipse
A 90kg astronaut and a 3800kg Satellite are in orbit about the earth with the same orbital radius. Which one is accelerating faster?
They are the same! Mass of the object that is orbiting doesn't affect acceleration, it only affects Force!
A new moon called Chongland is discovered! It orbits Venus with an orbital radius of 2.84*10^13m . Which Period equation would you use to solve for the period of Chongland?
T=2\pi\sqrt(r^3/(GM))
There is nothing else to compare Chongland with, you only have the radius and can use the table to find the mass of Venus. So this is the only option!
An asteroid of mass m is orbiting a star of mass M with an orbital radius of r. The force of gravitational attraction between the two is F. If the mass of the star were to be changed to 4M, what would the new orbital radius have to be in order to keep the Force the same?
r_2=2r
What is Kepler's 2nd Law?
A planet moves faster when it is closer to the Sun in its elliptical orbit, and slower when it is further away.
The Fortnite Battle Bus has a mass of 600kg and orbits about the Earth 1200km above the Earths surface. Calculate the velocity of the Battle Bus.
r=(1200*1000)+6.38E6=7580000
v=\sqrt((G5.98E24)/7580000)=7254m/s
The distance between Neptune and the Sun is 30.06AU. Calculate the time for Neptune to orbit the Sun in Earth years.
(T_a/(1 Earth Year))^2=((30.06AU)/(1AU))^3
T_a=164.8 Earth Years
Ganymede has a mass of 1.48*10^23kg and orbits about Jupiter 1.00*10^6km above the surface.
Calculate the gravitational force between Ganymede and Jupiter.
F_g=(G*1.48E23*1.9E27)/((1E6*1000)+7.15E7)^2
=1.63E22
Write the equation for Kepler's 3rd Law
(T_a/T_b)^2=(r_a/r_b)^3
Calculate the orbital speed of Venus orbiting around the Sun.
v=\sqrt((G*1.99E30)/(1.08E11)
v=35057m/s
Due to public backlash, Taylor Swift has decided to permanently live in her $54,000,000 jet in orbit above Pluto to avoid any more scrutiny. Give the orbital period of the 22,225kg jet that is orbiting above Pluto at an altitude of 1400km above the surface in hours.
r=(1400*1000)+1.2E6=2600000
T=2\pi\sqrt((2600000^3)/(G*1.25E22))=28848.4 seconds
28848.4/3600=8.0 hours