In what quadrant is
(20pi)/7
II
sec((15pi)/13)=
-1.129
cos 300o =
1/2
What is the ratio of sides for a 30-60-90 triangle?
What is the length of the shortest leg? Longest Leg? Hypotenuse

Find csc x if
sin x = sqrt(5)/4
(4sqrt(5))/5
Find a positive and negative coterminal angle. (Do not use the given angle as an answer.)
(19pi)/10
(39pi)/10, (-pi)/10
cot(228^o 45'')=
0.9
tan(-(2pi)/3)=
sqrt(3)
Find 
cot(theta)
cot(theta)=12/5
Given: tan x = 3/4, cos x = 4/5
Find sin x
sin x = 3/5
What quadrant?
cos x > 0 and sin x < 0
IV
Convert to Degrees, Minutes & Seconds. (round to the nearest second)
(97pi)/51
342^o 21'11''
sec(theta)=-2
Where on the unit circle? Give the answer in degrees.
120o, 240o
Using trigonometry, find the value for x:

Cos 37 = adj / hyp
Cos 37 = x / 11
11 Cos 37 = x
x = 8.8
Find cos x if the angle is in Quadrant II and
sinx=sqrt(7)/4
cos x = -3/4
Given the value on the unit circle, find
csc (theta)=

13/12
Convert to radians
207^o 48' 2''
3.626
csc (-405o)=
-sqrt(2)

What is 19 feet
cot x = 5 & cos x < 0 Find csc x
csc x =-sqrt(26)
The terminal side of the angle goes through the point (-10, 24), find
sin theta
12/13
Find 
sin alpha
sin alpha=8/17
cot(-(25pi)/6)=
-sqrt(3)
Determine the length of FG to the nearest tenth.
17
tan x = (2sqrt(5))/5