Simplifying i's
i^3
What is -i
√(-49) + √(-64)
15i
(2 + i)/(3 - 4i)
What is (2+ 11i)/13?
the square root of -1
i
i^4
What is 1
√(-4) * √(-9)
5i
(5+3i)/(2-2i)
What is (1 + 4i)/2
Why do we need imaginary numbers?
To find the square root of negative numbers
i^8
1
√(-9)
3i
1/(2 + 3i)
What is (2-3i)/13?
Simplify the following: √(-36)
6i
i^2
-1
√(100)
10
-6/i
What is 6i?
√(36) + √(-36)
6 + 6i
√(-200)
10i√2
√(-81)
9i
-7/i
What is 7i?
(1 -3i)(2+4i)
14-2i
√(25) + √(-100)
5 + 100i