Simplifying i's
i^2=
-1
√(-49) + √(-64)
15i
(2+3i) + (4+7i)
6+10i
It's the conjugate of 2+ 3i
2-3i
Another name for imaginary numbers is
i^5
i
√(-4) * √(-9)
5i
(5+6i) + (4-2i)
9 + 4i
It's the conjugate of 12 - 3i
12 + 3i
The imaginary unit is defined to be
Is it i2 = -1?
i^ 27
-i
√(-9)
3i
(6+5i)- (3+2i)
3+3i
It's the conjugate of ( -14+ 2i )
( -14 - 2i )
i0 =
1
i^33
i
sqrt-98
7isqrt2
(2-7i) - (1-4i)
1-3i
It's the conjugate of ( -4 - 20i )
(-4 + 20i)
is it a + bi?
i66
-1
sqrt(-48)sqrt(-18)
-12sqrt(6)
(3 +4i)+(5+5i)
8 + 9i
It's the conjugate of ( -1/2 - 11i )
( -1/2 + 11i )
Is 22 a prime number?
No, its not because 2 * 11= 22. Prime numbers can only be obtain when you multiply them by 1.