Equation of a Line
Parallel to y=-2/3x+5 through the point (-3, -5)
y=-2/3x -7
(x + 1)(x - 8)
x2 - 7x - 8
4(x - 2) = 24
x = 8
4x-5
4
_
x5
-8x - 6 = -5x -27
x = 7
Parallel to y= -2x + 1 through the point (-1, 4)
y = -2x + 2
(3x - 10)(x - 2)
3x2 - 16x +20
2√(x - 3) = 8
x= 19
(3/4)-2
= 16/9
4(2x - 5) = -4
x = 2
Perpendicular to y = -1/6x + 7 through the point (1, 7)
y = 6x + 1
(2x - 10)(3x + 9)
6x2 - 12x -90
(x - 1)2 = 9
x = 4 and x = -2
a3b2(b-2)3
a3
__
b4
-2(-x +4) - 3x + 2 = -5
x = -1
Write the equation of a line passing through (-4, -2) and (-6, -5).
y= 3/2x + 4
(4x + 3)(4x - 3)
16x2 - 9
√(2x + 5) = 10
x = 47.5
3x-4
_____
x-2y-3
3y3
_____
x2
x - (-6.4x +3.2) = x
x = 0.5
Perpendicular to y = -4/3x + 7 through the point (4, 2)
y= 3/4x - 1
(5x + 2)2
25x2 + 20x + 4
13x/6 + 3x/2 = -22/3
x = -2
(3x-2)4
3
__
x8
x-7/2x-9 = 4/3
x = 3