Z-Score Basics
Interpret Z-Scores
z-score Applications
Properties of Normal Distribution
100

What does it mean if a z-score is 0?

The data value is the mean.

100

Interpret the z-score of 2.08 for an IQ score of 140.

An IQ score of 140 is 2.08 standard deviations above the mean.

100

In recent years, it was found that teenagers between ages 13 - 17 send/receive an average of 1740 text messages per month with a standard deviation of 550 text messages.

What is the z-score for a teenager who sends/receives 2150 text messages per month?

0.75

100

Why is this not a normal distribution?


It is bimodal while Normal distributions are unimodal.

200

What does it mean if a z-score is positive?

The data value is above the mean.

200

Interpret the z-score of -2.5 for an exam score of 68 on a statistics exam.

A score of 68 is 2.5 standard deviations below the mean.

200

The Virginia Cooperative Extension reports that the mean weight of yearling (1-yo) Angus cattle is 1150 lbs. with a standard deviation of 80 lbs.

What is the z-score for a cow weighing 980 lbs.?

-2.13

200

Why is this not normal?

This is skewed left and Normal Distribution is symmetrical.

300

What does it mean if a z-score is negative?

The data value is below the mean.

300

If Martha scores a 64 on the history exam, interpret the z-score of -5.5 for her exam.

A score of 64 is 5.5 standard deviation below the mean.

300

In recent years, it was found that teenagers between ages 13 - 17 send/receive an average of 1740 text messages per month with a standard deviation of 550 text messages.

If a teenager has a z-score of 1.38, about how many text messages did he or she send/receive that month?

2499

300

Why is this not normal?


This is uniform and Normal is unimodal

400

Define z-score in your own words.

A z-score represents the number of standard deviations a data value is away from the mean.

400

Interpret the z-score of 0.75 for a teenager who sends/receives 2150 text messages per month.

2150 text messages is 0.75 standard deviations above the mean.

400

The Virginia Cooperative Extension reports that the mean weight of yearling (1-yo) Angus cattle is 1150 lbs. with a standard deviation of 80 lbs.

Is a cow weighing 1340 unusual? Explain.

Yes. The z-score is more than 2 s.d. from the mean.

400

Based on the given mean, median, and mode, can the distribution be normal?

Mode = 5

Median = 4

Mean = 3.5

No because the mean, median, and mode are the same in a Normal distribution.

500

Give the formula for calculating a z-score.

z = (x - mean) / sd

500

Interpret the z-score of -2.13 for a cow weighing 980 lbs.

A cow weighing 980 lbs is 2.13 standard deviation below the mean.

500

Give the formula to determine the data value associated with a given z-score.

x = (z)(s.d.) + mean

500

What happens to the Normal curve as the standard deviation increases?

The larger the standard deviation, the more spread out the data is so the shorter the curve.

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