quadratic functions
find axis of symmetry, y=-1/4 (x+2)^2+5
x=-2
find the value of, f(x)=2x+2
=4
f(x)1/3(x+4)^2-2
x=-4
3^2x+1-5=4
x=1/2
f(x)=3-2
no solution
identify vertex, y=x^2-10x+22
vertex is (5,-3)
find an equation of the linear function if, f(2)=5 and f(6)=3
f(x)=-1/2x+6
y=-4x^2-12x-8
(-2,0) and (-1,0)
3^x11=9^x-2
x=5
f(x)=3x^2-16x+21
x=7/3,3
find vertex, y=x^2+8x+5
vertex is (-4,-11)
f(x)=mx+(3-2 m)
(-2,-4)
y=x^2-4x+3
(2,-1)
4^x-2=0,125
x=0,5
f(x)=4x^2-35x+9
x=35/8
find axix of symmetry, y=-(x-3)^2+4
x=3
f(2)=-4
(2,-4)
y=x^2-4x+3
(0,3)
(25/100)^x=4^3x-2
x=1/2
f(x)=1x^2-2x+9
x=1
find vertex, y=x^2+12x+32
(-6,-4)
f(5)=-3
(5,-3)
f(x)=x^2-2x-3
(0,-3)
3^4x=21
x=.693
f(x)=5x^2-9x+8
x=9