Meselson and Stahl
DNA Discovery
Genetics
DNA Enzymes
DNA Enzymes 2
100


Meselson and Stahl were able to identify the semi-conservative replication of DNA by using labeled nitrogen isotopes. Which of the following reflects the result of their investigation that proves that DNA undergoes a semi-conservative replication process?

A) DNA replication results in one molecule that consist of the original DNA strand and one molecule that consist of the new strands.
B) DNA replication results in two molecules in which the individual strand is a patchwork of original and new DNA.
C) DNA replication results in two molecules of the original strand.
D) DNA replication results in two molecules with one original strand and one new strand.


D

100

The Hershey and Chase experiment served as powerful independent confirmation that DNA was indeed the genetic material. They made their discovery using which type of organism?

S. pneumoniae

mice

strains of bacteria

bacteriophage

bacteriophage

100

In the Hershey-Chase experiment, why was radioactive phosphorus (32P^{32}P32P) used to label DNA?
A. Phosphorus is only found in the sugar-phosphate backbone of DNA.
B. Phosphorus is unique to DNA and absent from proteins.
C. Phosphorus is incorporated into amino acids during protein synthesis.
D. Phosphorus is the only element found in bacteriophage DNA.

Answer: A. Phosphorus is only found in the sugar-phosphate backbone of DNA.

100

During DNA replication, why does DNA polymerase require a primer to initiate synthesis?
A. It needs a free 3'-OH group to add nucleotides.
B. It cannot bind to single-stranded DNA directly.
C. It requires ATP from the primer for energy.
D. It can only function on RNA templates.

Answer: A. It needs a free 3'-OH group to add nucleotides.

100

In prokaryotes, which DNA polymerase is primarily responsible for replacing RNA primers with DNA?
A. DNA polymerase I
B. DNA polymerase II
C. DNA polymerase III
D. RNA polymerase

Answer: A. DNA polymerase I

200


If we assume that DNA replication is according to the conservative model. Starting with 14N14N (lighter) DNA, and after two generations in the 15N medium, bacterial cells will produce the following band/s in density-gradient centrifugation.  


A) A single band of DNA with the lowest density
B) one band of DNA with the highest density and one band of DNA with the lowest density
C)A single band of DNA with intermediate density
D) A single band of DNA with the highest density


b

200

 In the famous Avery, MacLeod, and McCarty experiment, the tube that was treated with _______ resulted in the destruction of the "transforming material."

lipase

RNase

DNase

protease

DNAse

200

What genetic mechanism explains the coat color patterns in calico cats?
A. Autosomal recessive inheritance
B. X-inactivation causing random silencing of coat color alleles
C. Polygenic inheritance influenced by environmental factors
D. Y-linked inheritance determining coat color

Answer: B. X-inactivation causing random silencing of coat color alleles

200

What feature of DNA polymerase ensures high fidelity during replication?
A. Its ability to synthesize both leading and lagging strands.
B. Its proofreading activity via 3'→5' exonuclease function.
C. Its rapid elongation rate during synthesis.
D. Its inability to synthesize de novo.

Answer: B. Its proofreading activity via 3'→5' exonuclease function.

200

What is the role of single-strand binding proteins (SSBs) during DNA replication?
A. To synthesize primers for DNA polymerase.
B. To unwind the DNA double helix.
C. To prevent reannealing of separated DNA strands.
D. To add nucleotides to the growing DNA strand.

Answer: C. To prevent reannealing of separated DNA strands.

300


Starting with 14N14N (lighter) DNA, and after two generations in the 15N medium, bacterial cells will produce the following band/s in density-gradient centrifugation:  

A)a single band of DNA with the highest density
B)one band of heavier DNA and one band of DNA with medium density
C)one band of the lighter DNA with medium density and one band of DNA with the highest density
D)a single band of DNA with the lowest density


C

300

When Frederick Griffith coined the term "transformation," this was in reference to the genetic re-programming of

strains of bacteria.

laboratory mice.

patients with pneumonia.

bacteriophages 

strains of bacteria.

300

Why are male calico cats extremely rare?
A. Coat color genes are autosomal, and males lack the gene.
B. Males usually carry only one X chromosome and cannot be heterozygous for coat color.
C. Barr body formation prevents coat color variation in males.
D. Male calico cats result from a rare mutation in autosomal genes.

Answer: B. Males usually carry only one X chromosome and cannot be heterozygous for coat color.

300

Which enzyme prevents supercoiling ahead of the replication fork during DNA replication?
A. Helicase
B. DNA polymerase
C. Topoisomerase
D. Primase

Answer: C. Topoisomerase

300

Why does the synthesis of the lagging strand pose a challenge for DNA polymerase?
A. DNA polymerase cannot bind to the lagging strand directly.
B. The lagging strand is synthesized in the 5'→3' direction away from the replication fork.
C. DNA polymerase is unable to attach to RNA primers.
D. The lagging strand contains more A-T base pairs, requiring slower synthesis.

Answer: B. The lagging strand is synthesized in the 5'→3' direction away from the replication fork.

400

Meselson and Stahl transferred the bacteria from 15N medium to 14N medium. They allowed them to replicate for two generations. DNA extracted from these cells is centrifuged. The DNA obtained after the first round of replication is

A)Hybrid of one lighter and one heavier strand

B) Dense with both heavier strands
C) Lighter with both lighter strands
D) Have two density classes


a

400

Which experimental evidence directly led Watson and Crick to propose the double-helix model of DNA?
A. Chargaff's rules showing A=T and G≡C ratios
B. X-ray diffraction data showing a helical structure
C. Experiments showing DNA as the transforming principle
D. Density gradient experiments confirming semiconservative replication

Answer: B. X-ray diffraction data showing a helical structure

400

What would happen if X-inactivation did not occur in females?
A. All females would display uniform coat color patterns like males.
B. Females would express twice the amount of X-linked gene products compared to males.
C. Barr bodies would form in both males and females.
D. Females would have no active X chromosomes.

Answer: B. Females would express twice the amount of X-linked gene products compared to males.

400

Why are Okazaki fragments necessary during DNA replication?
A. The leading strand cannot synthesize DNA continuously.
B. DNA polymerase synthesizes DNA only in the 3'→5' direction.
C. The lagging strand is synthesized discontinuously due to antiparallel DNA strands.
D. DNA ligase needs fragmented DNA to function.

Answer: C. The lagging strand is synthesized discontinuously due to antiparallel DNA strands.

400

Telomerase is essential for maintaining chromosome length in eukaryotic cells because:
A. It synthesizes RNA primers for replication.
B. It adds repetitive sequences to the ends of chromosomes to prevent shortening.
C. It unwinds the DNA helix at telomeres.
D. It prevents mismatches during replication.

Answer: B. It adds repetitive sequences to the ends of chromosomes to prevent shortening.

500

Meselson and Stahl conducted an experiment to demonstrate that DNA replication is semiconservative. Imagine you perform a similar experiment, growing E. coli in a medium containing heavy nitrogen (15N^{15}N15N) for many generations. Then, you switch the E. coli to a medium with light nitrogen (14N^{14}N14N) and allow the bacteria to replicate their DNA.

You extract DNA after one generation and centrifuge it in a cesium chloride gradient. You observe a single band at an intermediate density.


  • What does this single band indicate about the nature of DNA replication?
  • Predict the band pattern if DNA was extracted after the second generation and centrifuged.
  • Suppose DNA replication was conservative instead of semiconservative. What band pattern would you observe after the first and second generations?
  • If you allowed the E. coli to continue replicating for three more generations, what would you observe in the banding pattern for semiconservative replication?
  • What does this single band indicate about the nature of DNA replication?

    • The single band at intermediate density indicates that DNA replication is not conservative. This intermediate density band shows that each DNA molecule contains one strand of the heavy (15N^{15}N15N) isotope and one strand of the light (14N^{14}N14N) isotope. This supports the semiconservative model of replication, where one parental strand is retained in each daughter molecule.
  • Predict the band pattern if DNA was extracted after the second generation and centrifuged.

    • After the second generation, there will be two bands:
      • One intermediate-density band (hybrid DNA: one 15N^{15}N15N strand and one 14N^{14}N14N strand).
      • One light-density band (DNA containing two 14N^{14}N14N strands).
      • The proportion of the light band will increase as more generations pass.
  • Suppose DNA replication was conservative instead of semiconservative. What band pattern would you observe after the first and second generations?

    • In conservative replication:
      • After the first generation, there would be two distinct bands: one heavy band (15N/15N^{15}N/^{15}N15N/15N) and one light band (14N/14N^{14}N/^{14}N14N/14N), because one molecule remains entirely heavy and the other is entirely light.
      • After the second generation, the same two bands would be present, but the proportion of the light band (14N/14N^{14}N/^{14}N14N/14N) would increase as new DNA molecules are synthesized using 14N^{14}N14N.
  • If you allowed the E. coli to continue replicating for three more generations, what would you observe in the banding pattern for semiconservative replication?

    • After three additional generations (five total generations):
      • The light-density band (14N/14N^{14}N/^{14}N14N/14N) would dominate, as most of the DNA molecules consist of two light strands.
      • The intermediate-density band (15N/14N^{15}N/^{14}N15N/14N) would still be present but would become progressively smaller with each generation.
500

Which observation from Griffith’s transformation experiment suggested that DNA could transfer genetic information?
A. Smooth (S) strain bacteria killed mice, while rough (R) strain did not.
B. Heat-killed S strain could transform live R strain into virulent S strain.
C. DNAase treatment prevented transformation in R strain.
D. Proteinase treatment did not prevent transformation in R strain.

Answer: B. Heat-killed S strain could transform live R strain into virulent S strain.

500

A pedigree is presented where a rare genetic condition affects multiple generations. Analyze the following pedigree description and answer the questions below:

Description

  • The condition affects both males and females.
  • Affected individuals are present in every generation.
  • An affected father passes the condition to all his daughters but none of his sons.
  • Unaffected individuals do not transmit the condition to their offspring.
  1. What is the most likely mode of inheritance for this condition?
    A. Autosomal dominant
    B. Autosomal recessive
    C. X-linked dominant
    D. Y-linked

  1. If the affected father has three daughters and two sons with an unaffected mother, what percentage of his daughters would be expected to inherit the condition?
    A. 0%
    B. 50%
    C. 100%
    D. 75%

  1. Which of the following statements would confirm that the condition is X-linked dominant rather than autosomal dominant?
    A. The condition is equally distributed between males and females.
    B. The condition is passed from an affected mother to all her children.
    C. The condition is never passed from father to son.
    D. The condition skips generations in some cases.

  1. If an affected mother (heterozygous) and an unaffected father have children, what is the probability that a son will inherit the condition?
    A. 0%
    B. 25%
    C. 50%
    D. 100%

  1. If the condition was Y-linked instead, which of the following would be observed?
    A. Affected females but not males.
    B. Affected fathers passing the condition only to their sons.
    C. Equal transmission of the condition to sons and daughters.
    D. The condition skipping generations in males.

  1. Which of the following rules applies to X-linked dominant inheritance but not autosomal dominant inheritance?
    A. Both males and females are equally affected.
    B. Unaffected individuals do not transmit the condition.
    C. Affected males pass the condition to all daughters but no sons.
    D. The condition appears in every generation.

Answer: C. X-linked dominant
Answer: C. 100%
Answer: C. The condition is never passed from father to son.
Answer: C. 50%
Answer: B. Affected fathers passing the condition only to their sons.
Answer: C. Affected males pass the condition to all daughters but no sons.

500

Telomerase plays a critical role in maintaining chromosome stability in eukaryotic cells.

  1. Describe the function of telomerase and its significance in the replication of linear chromosomes.
  2. Explain why telomerase activity is often higher in stem cells and cancer cells compared to somatic cells.
  3. Predict the consequences for a cell if telomerase activity is absent. Provide examples of disorders or diseases associated with defective telomerase function.


Answer:

  1. Telomerase is an enzyme that adds repetitive nucleotide sequences (e.g., TTAGGG in humans) to the ends of linear chromosomes (telomeres). During replication, the lagging strand cannot be fully synthesized at the 3' ends, leading to progressive shortening of chromosomes. Telomerase prevents this shortening by extending the template strand, allowing the synthesis of complete lagging strands.

  2. Telomerase activity is higher in stem cells and cancer cells because these cells undergo frequent divisions. Without telomerase, stem cells would lose essential genetic material, leading to senescence or apoptosis. In cancer cells, telomerase activity is upregulated, enabling unlimited division and contributing to cellular immortality.

  3. In the absence of telomerase, telomeres shorten with each cell division, eventually triggering DNA damage responses, cellular senescence, or apoptosis. Disorders associated with defective telomerase function include dyskeratosis congenita, which leads to premature aging, bone marrow failure, and other degenerative symptoms.

500

DNA replication involves the coordinated synthesis of leading and lagging strands at the replication fork.

  1. Compare and contrast the synthesis of the leading strand and the lagging strand.
  2. Discuss the roles of DNA polymerase, primase, ligase, and helicase in lagging strand synthesis.
  3. Explain why the lagging strand is more prone to replication errors and how the cell mitigates these risks.


Answer:

  1. The leading strand is synthesized continuously in the 5'→3' direction toward the replication fork. The lagging strand is synthesized discontinuously in the 5'→3' direction away from the replication fork, forming short Okazaki fragments.


    • Helicase: Unwinds the DNA double helix to expose single-stranded DNA.
    • Primase: Synthesizes RNA primers for each Okazaki fragment, providing a free 3'-OH group for DNA polymerase.
    • DNA Polymerase: Extends the primers by adding complementary nucleotides to synthesize Okazaki fragments.
    • Ligase: Joins the Okazaki fragments by sealing the phosphodiester bonds between adjacent fragments.
  2. The lagging strand is more prone to replication errors because it requires frequent priming, synthesis, and ligation of Okazaki fragments, increasing the likelihood of mismatches or gaps. Cells mitigate these risks through proofreading by DNA polymerase (3'→5' exonuclease activity) and mismatch repair mechanisms, which identify and correct replication errors after synthesis.

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