zero product property
when one of the factored terms is (x-2)
when the zero is x=2
how many solutions do intersecting lines have? and is it independent or dependent?
one solution and independent
solve for z
2<z–5–8z≤1
-1>z>=-20/7
multiply x(x+1)
x^2+x
when the equation is x^2+14x+48
when the zeros are x=-6x=-8
the solution to the system: 2x+3y=6 & 3x+5y=15
(-15,12)
solve for d
4(d-8)<16
d<12
multiply -3x(x-4)
-3x^2+12x
when the zeros are x=2 & x=-5
when the equation is y=(x-2)(x+5)
the solution to the system of equations: r+s=-6 & r-s=-10
(-8,2)
solve for s
s+19<5 or s-19>-8
s<-14 or s>11
multiply: -5x(-y+4)
5xy-20x
when the equation is x^2+6x+5
when the factors terms are (x+5) & (x+1)
the solution to the system: 8a+5b=9 & 2a-5b=-4
(0.5,1)
solve for c
-1(c-9)-14<=-13
c>=8
multiply: 4x^2(5x-y)
20x^3-4x^2 2y
when the zeros are x=8 & x=2
when the equation is x^2-10x+16
the solutions to the system t+u=12 t=(1/3)u
(3,9)
solve for v
-18<=-5v+2+2v<12
20/3>=v> -10/3
multiply: 3xy(xy-1)
3x^2y^2-3xy