Definition
Substitution
Factorization
L 'Hospital's Rule
Problems
100

What is limit in calculus?

A limit tells us the value that a function approaches as that function's inputs get closer and closer to some number.

100

What is substitution?

is a method of determining limits where the value that x is approaching is substituted into the function and the result is evaluated

100

What is finding limit by factoring?

By canceling out common factors

100

What is L 'Hospital's Rule?

It says that the limit when we divide one function by another is the same after we take the derivative of each function

100

limx→2(8−3x+12x2)

50

200
Who found limit in Calculus?

In the 19th century, Augustin-Louis Cauchy, Karl Weierstrass, and Bernhard Riemann reformulated calculus in terms of limits, rather than infinitesimals.

200

When can you use direct substitution for limit?

when you have a simple functions with additions, subtractions, divisions, multiplications, powers and roots

200

How do you use the factorization formula? 

To write an algebraic expression as the product of two or more expression
200

What is L 'Hospital's Formula?

lim x->c f(x) / g(x) = lim x->c f'(x) / g'(x)

200

lim x->-3 (6+4t) / (t^2+1)

-3/5

300

What is the basic concept of limits?

Limits are essential to calculus and mathematical analysis, and are used to define continuity, derivatives, and integrals

300

lim x->3 (x^2 - 4) / (x - 2)

5

300

(a + b)^2 = ?

a^2 + 2ab + b^2

300

How to apply L 'Hospital's Rule?

  • First check whether f(a)/g(a) results in an indeterminate form such as 0/0, ∞/∞, etc.
  • If so, find the derivatives f'(x) and g'(x).
  • Then the given limit is obtained by evaluating the limit lim x → a f'(x)/g'(x).
300

lim h->0 [(6+h)^2 - 36] / h

12

400

What are three ways to solve limits?

substitution, factoring, and the conjugate method.

400

lim x->4 [3(x - 1)] / (x + 4)

9/8

400

(a - b)^3 = ? 

a^3 - 3a^2b + 3ab^2 - b^3

400

lim x->2 (x^3 - 7x^2 + 10x) / (x^2 + x - 6)

-6/5

400

lim x->-5 (x^2 - 25) / (x^2 + 2x - 15)

5/4

500

How are limits useful in daily life?

 It helps to measure the strength of the magnetic field, electric field, etc. Limits are used to figure out the most relevant pieces of information from the large complex functions.

500

lim x->5 (5x)^1/2 - 12

-7

500

(a + b + c)^2 = ?

a^2 + b^2 + c^2 + 2ab + 2bc + 2ca

500

lim x->∞ [ln(3x)] / x^2

0

500

lim x->4 (x^1/2 - 2) / (x - 4)

1/4

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