When simplifying an equation, Jayden got that 1=2. He then wrote that there were no solutions. Is Jayden's thinking True or False?
True! 1 does not equal 2, so there are no x-value solutions that can make 1 equal 2
When simplifying an equation, one found that 6 = 7. How many solutions does this equation have?
No solutions! No value of x will make 6 = 7
a+b=c
Solve for a
a=c-b
x^2 * x^3 =
x^5
What is the slope intercept form of a linear equation?
y = mx + b
With the following equation
a+b+c=d
If you solve for c, you'd have:
a=b+c+d
True or False?
False: It should be
a=d-b-c
When simplifying an equation, Abel got 0=0. How many solutions does this have?
Infinitely many solutions
f/g=h
Solve for f
f=gh
Anything raised to the 0th power is?
So
67^0 =
1
What is a quadratic?
A polynomial defined by the
x^2
term
Is the correct solved form of the variable "m" for this equation?
mn=fg
m=fgn^-1
True! Remember, a negative exponent means that variable is in the denominator of a fraction.
When simplifying an equation, Jesus got that x = 2. How many solutions?
1 solution
ac+b=d
Solve for c
c=(d-b)/a
x^3/x=
x^2
How would you algebraically write out:
Five less than the square root of a number
sqrt(n) - 5
In the following equation:
kx+6=7+6x
Johana found that if k=6, there would be infinitely many solutions
FALSE: if k=6 there would be NO SOLUTION
How many solutions does the following equation have?
6x+7=5+x+5x+2
Infinitely many solutions!
(a+b)/(c+d) = f
Solve for a
a=f(c+d)-b
or
a=fc+fd-b
(x^3 * x^2)/x^6 =
x^-1
or
1/x
How do the x-intercepts relate to a quadratic?
They tell you the solutions of the quadratic or help you find the factored form
Use the following equation
(ab)/(cd) =f
Is this solved form for a?
a=(fcd)/b
True!
How many solutions would the following equation have:
3(x+1)-2=3x+3
No Solutions!
(ax+by)/(c+d)=fg
Solve for x
x=(fg(c+d)-by)/(a)
(x^6 * x^7)/(x^3)^4
x
How do you factor?
You multiply a and c, while also looking at b.
You want a SINGULAR pair of number that multiplies to ac while also adds to be equal to b.
EXAMPLE:
x^2 + 7x + 12
Then ac=12 and b=7. The singular pair of numbers is 4 and 3. Thus:
x^2+7x+12=(x+4)(x+3)