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100

Evaluate log 60

1.7782

100

f(x)= 2( 5)x   

Find the domain and range

Domain ALL REAL NUMBERS

Range Y>0

100

natural logarithm ln has what base?

e

100

Two types of logarithms 

What is natural logarithms and common logarithms

100

Solve ln (3x+2) =1

0.3591

200

Evaluate ln 666 

6.5013

200

f(x)= 2( 5)x   

Find the y-intercept and Asymptote

y-intercept 2

asymptote y=0

200

Rewrite 2 = 16 in logarithmic form.

log2(16) = 4

200

If you deposit $4000 into an account that pays 5% interest quarterly, how much money is in the account in 3 years?

$4643.02

200

Solve log (4x-2) =1 

3

300

Evaluate log5(-125)

Does not exoist

300

f(x)= 2( 5)x   

Describe the end behavior

x--> -oo     y--> 0

x--> +oo    y--> oo

300

Rewrite in exponential form log10(1000) = 3

103  = 1000

300

You started a podcast in 2015, find the exponential model if you had 150 followers in 2020 and 199 followers in 2021. Round to the nearest tenths. 

How many followers do you have in 2026?

f(x)=36.5(1.33)x  

840

300

Solve ex+5 =8 


-2.9206

400

Evaluate log0.25(81)

-3.1699

400

f(x)= 2x  is translated to g(x)= -3(2)x-4 +5 

describe all the translations

x axis reflection, vertical stretch, 4 right, 5 up 

400

Common logarithm log has what base

10

400

The function f(x)= 450(1.05)x model the population of falcons in Tennessee. 

Is the number increasing or decreasing?

What is the staring population of the falcons? 

increasing

450

400

Solve 20 = 10x+2  


-0.6990

500

Evaluate  e1.25

3.4903

500

f(x)= 2x  is translated to g(x)= 0.2(2)x+5   - 4

describe all the translations


vertical compression, 5 left, 3 down

500

The function f(x)= 450(1.05)x model the population of falcons in Tennessee. 

What is the growth factor?

What is the growth rate?

1.05

5%

500

If the population of snipes in Jackson County in 2020 was 450 and the decay rate is 1.3% each year. Write the decay function that models the snipe population.

Use the model to find the population in 2024.

f(x)=450(1.013) 

473

500

If $2000 was invested 5 years ago, and the interest 2.5% was compounded continuously, what is the account worth today?

$2266.30

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