Convert log3x(3)=3 into exponential form.
(3x)3=3
Condense log(x)+log(y)
log(xy)
Solve log749
2
Solve e3x=4
.462
A new car is purchased for $15,300. The value of the car depreciates at 10.25% per year. What will the value of the car be, to the nearest cent, after 7 years?
7176.83
Convert log2x(2)=5/3 into exponential form.
(2x)5/3=2
Condense log(g)-log(q2)
log(g/q2)
Solve log6216
3
Solve 2e3x=8
1/2
$6,500 is placed in an account with an annual interest rate of 7.5%. How much will be in the account after 21 years, to the nearest cent?
29681.86
Convert 62=36 into log form.
log6(36)=2
log(bzg)
Solve log32(1/64)
-6/5
Solve 3ex+4=10
.693
7,900 dollars is placed in a savings account with an annual interest rate of 3%. If no money is added or removed from the account, which equation represents how much will be in the account after 5 years?
7,900(1.03)5
Convert 6-3/2=1/√216 into log form.
log6(1/√216)=-3/2
Condense log(g)+k log (q)
log(gqk)
Solve log27(1/243)
-5/3
Solve 1−8 ln(2x−1/7)=14
1/2(1+7e-13/8)=1.1892
Your chicken coupe of 23 chickens triple every year. Which equation matches the number of chicken after 2 year?
23(3)2
Convert log10(x2+3x+14)=1/4 into exponential form.
101/4=x2+3x+14
Condense 8 log(q) -z log(d)
log(q8/dz)
Solve log1
0
Solve log(w)+log(w−21)=2
25
You have a collection of baseball cards that is worth $210. If the cards appreciates at a rate of 12.1% per year, which equation represents the value of the cards after 3 years?
V=210(1+0.121)(1+0.121)(1+0.121)