Factoring
Solving Systems of Equations
Word Problems
Solving for a variable
Factoring x2
100

Factor. 

28 v3 w2  y4 + 24 vw9

4v3 w2 (7y4 + 6v4 w7)


100

Solve the following system of equations.

3x + 4y = 8 

5x − 3y = 23

x = 4 

y = −1

100

Two mechanics worked on a car. The first mechanic worked for 20 hours, and the second mechanic worked for 15 hours. Together they charged a total of $2075. What was the rate charged per hour by each mechanic if the sum of the two rates was $120 per hour?

First mechanic: $55 per hour 

Second mechanic: $65 per hour

100

Solve for y.

y2 + 2y − 8= 0

y=-4, 2

100

Factor.

y2-11y+18

(y-2)(y-9)

200

Factor. 

2u2 + 22u + 48

2(u+3)(u+8)

200

Use substitution to solve the system.

5x + 3y = 10 

y = 2x + 7

x = −1 

y = 5

200

The length of a rectangle is 3 m less than twice the width, and the area of the rectangle is 44 m2. Find the dimensions of the rectangle.

Length: 8 m

Width: 5.5 m

200

Solve for v. 

 v2 + 2v − 3 = 0

v = −3, 1

200

Factor.

x2-9xy+20y2

(x-4y)(x-5y)

300

Factor.

x+ 16x + 64

(x+8)2

300

Solve the following system of equations.

(3/4)x +(1/2)y =−10 

(-1/3)x + (1/6)y = 6

x = −16 

y = 4

300

A chef is going to use a mixture of two brands of Italian dressing. The first brand contains 7% vinegar, and the second brand contains 12% vinegar. The chef wants to make 300 milliliters of a dressing that is 8% vinegar. How much of each brand should she use?

First brand: 240 milliliters 

Second brand: 60 milliliters

300

Factor.

5z2 + 7z + 2

(z+1)(5z+2)

400

Factor. 

27+ 8v3

(3 + 2v) (9 − 6v + 4v2)

400

Solve the following system of equations.

(1/2x) - (1/3y) =−5 

2x − (1/5y)= (2/5)

x = 2 

y = 18

400

A motorboat travels 188 kilometers in 4 hours going upstream. It travels 284 kilometers going downstream in the same amount of time. What is the rate of the boat in still water and what is the rate of the current?

Rate of the boat in still water: 59 km/h

Rate of the current: 12 km/h

400

Factor.

25z2 −  81y2

(5z+9y)(5z-9y)

500

Factor.

6x2 − 5x − 4

(3x-4) (2x+1)

500

Last year, Linda had $10,000 to invest. She invested some of it in an account that paid 6% simple interest per year, and she invested the rest in an account that paid 9% simple interest per year. After one year, she received a total of $690 in interest. How much did she invest in each account?

First account: $7000

Second account: $3000

500

Factor. 

63-28y2

7(3+2y) (3-2y)

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