Operations with Negatives
Multiplying Binomials
Factor Quadratics
Functions
Find f(4)
100

(-3)(5)

-15

100

3(2x+5)

6x + 15

100

x^2+5x+6

(x+2)(x+3)

100

f(x)=x+2


f(4)=

f(4)=6

200

(5)+(-9)

-4

200

-2(3x-4)

-6x + 8

200

x^2+2x+1

(x+1)(x+1)

200

f(x)=\frac{x+2}{3}


f(4)=

f(4)=2

300

(-10)-(10)

-20

300

(x+2)(x+3)

x+ 5x + 6

300

x^2-6x+8

(x-4)(x-2)

300

f(x)=(\frac{x+2}{3})^2


f(4)=

f(4)=4

400

6-2

1/36

400

(x+4)(x-5)

x- x - 20

400

x^2-25

(x-5)(x+5)

400

f(x)=x(\frac{x+2}{3})^2


f(4)=

f(4)=16

500

8^-\frac{1}{3}

1/2

500

(x-4)(x^2-3x+5)

x^3-7x^2+17x-20

500

2x^2+7x+3

(2x+1)(x+3)
500

f(x)=x(\frac{x+2}{3})^(2x)


f(4)=

f(4)=1024

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