Finding Numerical Values
3X - 5=4
X=3
R2 - R= 0
R(R-1)=0
R=0 R=1
X2 + 6X + 5
(X + 5)(X + 1)
Graph 1
y= 2x +3
X2 - X
X( X- 1)
Factoring Binomials
1*2= -W/6
W=-12
3Y2 - 12Y= 0
3Y(Y-4)=0
3Y=0
Y= 0 Y=4
C2 - 9C + 18
(C - 6)(C - 3)
Graph 2
y = 2x + 4
y2 - 2y - 3
(y - 3)(y + 1)
Factoring Trinomials
-7= -8-12t
t= -1/12
9X2 - 12X= 0
3X(3X - 4)= 0
X=0 X=4/3
a2 + 3a - 28
(a - 4)(a + 7)
Graph 3
y = -x
y= 2x
x + y= 24
Solving by Substitution
8X/2 + 6= 2
X=-1
5KJ2 - 20K= 0
5K(J2 - 4)= 0
5K=0 J2 -4=0
K=0 J=2
S2 -12S + 3
Prime
Graph 4
y = 1/2 x - 3
5 + 8 + 11 + 14 + 17
D= 3
Arithmetic Series
3X + 2X -3 +4 = 26
X=5
3P2 - 12=0
3(P2 - 4)= 0
P2 - 4= 0
P=2
X2 + 9X - 21
Prime
Graph 5
y = -2/3 x - 1
8 + 20 + 50 +125
R= 2.5
Geometric Series