If 6abc = 0 what do you know about a, b, and/or c?
One of these factors variable factors (a, b, and/or c) must = 0
Solve:
x^2 = -9
No real solution (wait for Math 22)
How does the discriminant determine the number of real solutions in a quadratic equation?
b^2-4ac
> 0 there are 2 real solutions
<0 there are no real solutions
=0 there is one real solution
Solve:
x^4 - 2x^2 -24
sqrt6, -sqrt6
Simplify
(-64)^(2/3)
16
Solve:
3x^2 -27=0
x = -3, 3
Solve:
8x^2+4=-x^2+40
x = -2, 2
Solve:
2x^2 -5x+6=0
no real solution
Solve:
2x^4=32x^2
0, -4, 4
Solve:
(x-5)^(2/3)-6=10
x= -59, 69
Solve:
2x^2 -5x=3
x = -1/2, 3
Solve:
3(x-1)^2=48
x = -3, -5
Solve:
2x^2+3=8x
2+sqrt10/2, 2-sqrt10/2
Solve:
2sqrt(x+1)-3=9
x = 35
Solve:
(x+1)^(3/2)+2=10
x = 35
Solve:
5x^3 - 40=0
x = 2
4(x+3)^2-7=5
x=-3-sqrt3, -3+sqrt3
Solve:
3x^2-x=5
1/6+sqrt61/6,1/6-sqrt61/6
Solve:
sqrt(2x+9)-x=3
x = 0
Solve:
|x^2-2x|=-2x+4
x = -2, 2
Solve:
2x^2+6=8x
x = 1, 3
Solve:
-4(2x-1)^2+3=6
NO REAL SOLUTION
Solve:
-9x-5=-2x^2
-1/2, 5
Solve:
5∛(x+3)-2=18
x = 61
Solve:
|2x+2|=x^2-6
x =
-1-sqrt5, 4