Unit 6
Unit 7
Unit 8
Unit 9
Unit 10
First Quarter Material
First Quarter continued...
100
Solve for x and y
x=38 and y=25
100
Find side c:
c = 8√3
100
Graph the following circle:
(x+1)2+(y-3)2=16
100
Find the surface area and volume of a rectangular prism with a width of 5 inches, length of 8 inches, and a height of 3 inches.
V = 120 inches3
SA = 158 inches2
100
Find the probability of being a girl given that you are left handed. Write solution as a decimal rounded to the nearest hundreth.
12/29 = .41
100
Find the inverse of f(x) = 4x + 3 and verify using compositions.
f'(x) = (x-3)/4 or x/4 - 3/4
Prove f(f'(x)) = x
4((x-3)/4) + 3 = x (4's will cancel)
x - 3 + 3 = x
x = x
100
Graph and state the domain and range in interval notation:
y=2(3/2)^x
Domain: (-∞,∞)
Range: (0,∞)
200
TR||PA, ∠RTA = 6x, ∠PAT = 2x +16, ∠PTA = 6y - 12
Find x and y
x = 4 and y = 13
200
Find x. (Round to the nearest hundreth)
x = 11.98
200
Write the following equation in standard form:
x2+y2 - 8x + 6y - 11 = 0
(x-4)2+(y+3)2=36
200
Find the surface area of a cone with a diameter of 12 inches and a height of 8 inches. Leave your answer in terms of pi.
SA=96pi
200
In Mr. Cross' class there are 13 boys and 22 girls. If I select a group of 4 at random, calculate the following: (Write solutions as a decimal rounded to the nearest hundreth)
a) Probability that I select exactly 4 girls?
b) Probability that I select at least 3 boys? (3 boys and 1 girl or 4 boys)
a) 22C4/35C4 = 7315/52360 = .14
b) (13C3(22C1)+13C4)/35C4 = 7007/52360 = .13
200
Solve the following system algebraically:
y = (x+3)2 - 8
y = 2x+13
(-6,1) & (2,17)
200
Solve the following quadratic by the method of your choice:
6x2 -13x + 6 = 0
x = 2/3 & x = 3/2
300
Find angle Z. (Round to the nearest whole degree)
Angle Z = 32 degrees
300
Find angle PQR
Angle PQR = 92 degrees
300
Find the following given the equation y = 2x2 + 12x +16
a) AOS
b) Vertex
c) X-Intercepts
d) Graph
a) AOS x=-3
b) Vertex (-3,-2)
c) X-Intercepts: (-4,0) & (-2,0)
d)
300
Solve the following quadratic by the method of your choice:
-3(x-4)2 + 20 = -1
x = 4+-√7
400
∆ABC maps ∆A'B'C' with the following transformation: (x,y) -> (x+3, y-13) -> ((3/4)x, (3/4)y)
a) If BC=16, what B'C'?
b) If point A is at (1,5), what are the coordinates of A' after all the transformations?
a) B'C'=12
b) A'(3,-6)
400
Find the circumference and area of circle A, and angle D: (Leave in terms of pi) AB = 14
C = 28pi
A = 196pi
Angle D = 120 degrees
400
State the transformations, domain, range, and graph the following square root: (List domain and range in interval notation)
y=1/2sqrt(x+3)
What are vertical compression and left three
Domain:[-3,∞)
Range: [0,∞)
400
Solve:
-1/3abs(2x-4)+3=1
x = 5 and x = -1
500
Find the arc length of BC and the sector area formed by angle CAB: (Leave in terms of pi) AB = 14
Arc Length = (14/3)pi or 4.7pi
Sector Area = (98/3)pi or 32.7pi
500
Graph and identify the vertex, focus, and p-value:
(x+3)^2=-8(y-2)
Vertex: (-3,2), Focus: (-3,0), p-Value: -2
500
root3(81x^4y^12z^5)/root3(3x^-2y^6z^-4)
3x^2y^2z^3