Find the inverse of: f(x) = 2x
f-1(x) = log2x
Write the function: $100 grows at 3%
y = 100 (1.03)x
log4(4x - 1) = log4 (x + 5)
x = 2
log28
3
What is the y-int? f(x) = 1/4 (4) x
(0, 1/4)
Inverse of: f(x) = ln x
f-1(x) = ex
Describe the rate? y = 900(0.68)x
Down by 32% per year
ex + 1 = 2
x = -0.31
log162
x = 1/4
What is "e" to the nearest thousandth?
2.718
Inverse: f(x) = 3x - 2
f-1(x) = log3(x + 2)
Yearly growth rate? Year 1: 1800 Year 5: 3600
18.9% or 19%
2 + 3x = 8
x = 1.63
log25(1/5)
x = -1/2
Which has a faster rate of change? y = 4(2)x OR y = 4 (1/2)x
They're both the same.
f(x) = 3 log (x + 1) - 2
f-1(x) = 10(x+2)/3 - 1
How long will it take for $200 to grow to $600 if the interest rate is 10%?
11.5 years
log2(x - 1) + log2(x + 1) = 3
x = 3
ln e201
201
2 log x - 4 log y + 5 log z - 8 log a
log( x2z5 / y4a8 )
What is the asymptote of the inverse of: ln (x - 1) + 3 ?
y = 1
How long would it take to lose half your weight if you lost 15% per year?
4.3 years
log3(x) + log3(x - 1) - log3(x + 1) = log41
x = 2.41
3 log2781 + 6 log366
7
Make up your own word problem: y = 500(1.2)x
(you cannot use money)
Answers will vary