What is the first step for solving an equation using the quadratic formula?
Making sure the equation is in standard form, which means it should be equal to 0
Subtract (a3 -2a2) - (3a2 -4a3)
5a3 -5a2
Convert 2400 to radians
4 pi/ 3
-2x -5y +4z = 21
-5x -5y +z = 21
-4y -4z = 8
(-1, -3, 1)
x2 + 11x - 42 = 0 ?
X = 3 or x= -14
Subtract (3a2 +1)−(4+2a2)
a2-3
Convert 3150 to radians
7 pi/ 4
5x +y -4z = -4
-3y - 6z= -21
-x -y -z = -6
(5, -5, 6)
3x2 + 8x - 91 = 0 ?
X = -7 or x = 13/3
Subtract (3x4 −3x)−(3x−3x4)
6x4-6x
Convert 19 pi/ 4 to degrees
8550
-4x -6z = -12
-6x - 4y -2z = 6
-x +2y +z = 9
(-3,1,4)
X2 - 8x + 13 =0?
X = 4 +/- radical 3
Add (9r3 +5r2 +11r)+(−2r3 +9r−8r2)
7r3 -3r2 +20r
Convert pi/4 to degrees
450
4x -4y +2z = -14
4x +2y = 14
-3y + z = -10
No solution
X2 -6x -15=0?
X= 3 +/- 2 radical 6
Add (13n2+11n−2n4)+(−13n2 −3n−6n4)
-8n4 +8n
Convert -31pi/ 18 to degrees
-3100
X -3y + z = -7
-4x -6z = 4
2x +3y +2z = 4
( -1,2,0)