Ordered pairs
(2.1-2.3)
(2.1-2.3)
What are the x-intercept and y-intercept of the graph of:
3x+7y=21
x-intercept: (7,0)
y-intercept: (0,3)
Does the relation define a function?
{(5,3),(2,3),(3,4)}
Yes it is a function. Each x-value is different
Find the slope of the line containing (-5,3) and (8,4)
m= 1/13
Give the shape, key point (vertex, starting point, center), Domain and Range and also the Transformations of Function equation of:
y=|x|
V-shaped
Vertex (h,k)
Domain (-∞,∞)
Range [0,∞)
f(x)=a|x-h|+k
let f(x)=x2-5 and g(x)=1-x; Find (f/g)(-10)
(f/g)(-10)= 95/11
Create a table of values with 3 ordered pairs and graph the equation:
y=x2-8 Use: -2,0,2 as your x-values
Ordered pairs: (-2,-4),(0,0),(2,-4)
Graph is an upside down parabola with Vertex @ (0,0)
Yes y=x13 is a function.
Domain: (-∞,∞)
Range: (-∞,∞)
Find the slope of the line: Horizontal, through (6,2)
m=0
*Horizontal line always 0 slope*
Give the shape, key point (vertex, starting point, center), Domain and Range and also the Transformations of Function equation of:
y=x2
U-shaped
vertex (h,k)
Domain: (-∞,∞)
Range: [0,∞)
f(x)=a(x-h)2+k
let f(x)=2x2+2 and g(x)=-3x+3; Find (f-g)(-4)
(f-g)(-4)=19
Find the x-intercepts of: y=x2-9
x-intercepts: (3,0),(-3,0)
let h(x)=-x2+6x+2; Find and simplify h(-3)
h(-3)=-25
Write an equation in slope-intercept form.
Through (6,8) and parallel to y=-8
*might be helpful to use the Point-slope formula*
Slope-intercept form: y=8
Give the shape, key point (vertex, starting point, center), Domain and Range and also the Transformations of Function equation for:
y=x3
1/2 up-1/2 down parabola
Point of inflection (h,k)
Domain: (-∞,∞)
Range: (-∞,∞)
f(x)=a(x-h)3+5
(fg)(-6)=651
Find 3 ordered pairs for the equation and graph:
y=|x-8|
use -2,8,13 as the x-values
ordered pairs: (-2,10),(8,0),(13,5)
The graph is a v-shaped graph with vertex @ (8,0)
Is y=√5x+1 a function?
**5x+1 is under √**
Yes y=√5x+1 is a function.
Write an equation in slope-intercept form:
Through (-1,5) and parallel to x+2y=5
*might be helpful to put equation in slope-int form first then use the point-slope formula*
slope-intercept form: y=(-1/2)x+9/2
Give the shape, key point (vertex, starting point, center), Domain and Range and also the Transformations of Function equation for:
y=√x
Half sideways parabola
Starting point (h,k)
Domain: [0,∞)
Range: [0,∞)
f(x)=a(√x-h)+k
Let f(x)=x+2 and g(x)=x2; Find (GoF)(1)
(GoF)(1)=9
If a vertical line is drawn through the point (-2,3), at what point will it intersect the x-axis?
*Might be helpful to sketch the graph*
It will intersect at point: (-2,0)
Let f(x)={(6,3),(-1,6),(-3,7)}; Find f(6)
f(6)=3
Write an equation in slope-intercept form:
Through (1,6) and perpendicular to 2x+5y=1
slope intercept form: y= (5/2)x+7/2
Is this a function? Why or Why not?
x=y2
Not a function because it Does NOT pass the vertical line test.
let f(x)=4x-2 and g(x)=1/4(x+2)
find (gof)(x) and (fog)(x)
Then determine if (fog)(x)=(gof)(x)
(fog)(x)=x
(gof)(x)=x
Yes they = each other